The maximum value of quadratic function y = ax & # 178; + BX + C is 4, and the image passes through the point (- 3,0)

The maximum value of quadratic function y = ax & # 178; + BX + C is 4, and the image passes through the point (- 3,0)

If the maximum value of quadratic function y = ax & # 178; + BX + C is 4, then y = a (X-H) ^ 2 + 4, a

The image of the quadratic function y = ax & # 178; + BX + C passes through the point (- 1,0) to find the value of C / (a + b) - B / (a + C) - A / (B + C)

Because the function image is too (1,0),
So a + B + C = 0,
Then a + B = - C, a + C = - B, B + C = - A,
So C / (a + b) - B / (a + C) - A / (B + C) = - 1 + 1 + 1 = 1
(it seems that there is something wrong with the condition of the title, so I made a bold change.)

Given the quadratic function y = ax & # 178; + BX + C, when x = 2, the maximum value of Y is 3, and its image passes through the point (3,1), then its analytical formula is

When x = 2, the maximum value of Y is 3
The parabola is y = a (X-2) &# 178; + 3
And the parabola passing through the point (3,1)
∴1=a(3-2)²+3
∴a=-2
The analytic formula of parabola is: y = - 2 (X-2) &# 178; + 3 = - 2x & # 178; + 8x-5
Do not know, welcome to ask

It is known that the maximum value of quadratic function y = ax & # 178; + BX + C is 7, and the solution set of Y ≥ 0 is {x │ - 1 ≤ x ≤ 3}. The value of a, B, C is obtained

If x = - 1, y = 0
When x = 3, y = 0
The axis of symmetry is x = 1, where y = 7