If y = ax & # 178; + BX + C and X-axis intersection (- 2,0) (1,0), its shape and opening direction are the same as the parabola y = - X & # 178;, then the parabola analytical formula

If y = ax & # 178; + BX + C and X-axis intersection (- 2,0) (1,0), its shape and opening direction are the same as the parabola y = - X & # 178;, then the parabola analytical formula

According to the meaning of the question, we know that a = - 1, so the analytical formula of the parabola is y = - (x + 2) (x-1), that is, y = - x ^ 2-x + 2

If the intersection point of the parabola y = ax + BX + C and the X axis is (- 1,0) (3,0), and its shape is the same as the parabola y = - 2x, then the analytical formula of the parabola is

If the intersection point of the parabola y = ax + BX + C and the X axis is (- 1,0) (3,0), and its shape is the same as the parabola y = - 2x, then the analytical formula of the parabola is
y=-2(x+1)(x-3)
=-2(x²-2x-3)
=-2x²+4x+6
Or:
y=2(x+1)(x-3)
=2(x²-2x-3)
=2x²-4x-6

It is known that two points a (x1, O) and B (x2,0) of the parabola y = ax square + BX + C (a is not equal to 0), which are different from the x-axis, intersect with the positive half axis of the y-axis at point C

If X1 and X2 are the two roots of the equation x (x 1 ＜ x 2), and the area of triangle ABC is 15 / 2.if x0d (1), we can find the analytic formula of the sub parabola. If x0d (2), we can find the functional relationship between the line AC and BC. If P is a moving point on the line AC (not coincident with A.C.), if P passes through point P as a line y = m (M is a constant) and the line BC intersects at point Q, then whether there is a point R on the x-axis, Yes, a PQ is a waist of △ PQR is an isosceles right triangle? If it exists, find out the coordinates of point R; if it does not exist, please explain the reason

If the solution set of inequality ax + b greater than 0 is x greater than - 2, then the axis of symmetry of parabola y = ax square + BX + C is

The solution set of AX + b > 0 is x > - 2
a>0
x>-b/a
-b/a=-2
The axis of symmetry of y = ax square + BX + C is x = - B / 2A = - 1