Given that the distance between a point P on the parabola y square = 4x and its focus f is 6, then the coordinate of point P is

Given that the distance between a point P on the parabola y square = 4x and its focus f is 6, then the coordinate of point P is

(5, positive and negative root sign 20)

Given that the distance from a point P on the parabola y ^ 2 = 4x to the Y axis is 3, what is the distance from it to the focus of the parabola?

y^2=4x
P = 2, the Quasilinear equation is x = - P / 2 = - 1
By definition, the distance from point m to focus is 3

If the ratio of the distance between the point P and the Y axis on the parabola y2 = 4x and the distance between the point P and the focus is 13, then the distance between the point P and the X axis is 13______ ．

Let the point P (y24, y) on the parabola y2 = 4x, the focus coordinate (1, 0) of the parabola, and the ratio of the distance from the point P to the Y axis and the distance from the point P to the focus on the parabola y2 = 4x is 13, so y24 (y24 − 1) 2 + y2 = 13; the solution is y2 = 2; so the distance from P to the X axis is 2; so the answer is 2