If x = 1 / (1 / 1980 + 1 / 1981 + 1 / 1982 +... + 1 / 1998 + 1 / 1999), find the integer part of X

If x = 1 / (1 / 1980 + 1 / 1981 + 1 / 1982 +... + 1 / 1998 + 1 / 1999), find the integer part of X

Let s = 1 / 1980 + 1 / 1981 + 1 / 1982 +. 1 / 1999,
In the fraction, if the numerator is the same, the greater the denominator, the smaller the denominator
①S=1/1980 + 1/1981 + 1/1982 +...+1/1999>1/1999 + 1/1999 + 1/1999 +...+1/1999=20/1999
②S=1/1980 + 1/1981 + 1/1982 +...+1/1999

If x = 111980 + 11981 +11997, then the integral part of X is______ ．

181997＜11980+11981+… +11997 < 181980, so 198018 < 111980 + 11981 + +11997 ＜ 199718, that is 110 ＜ 111980 + 11981 + & nbsp &So the integral part of X is 110.95

On Jianbi (Mathematics): 32:48 12 / 7:24 / 5 12:5 / 4 24:72 1.6:6.4 7 / 2:5 / 3
It's not simplification, it's simplification!

Jane's ratio (Mathematics)
32:48=2:3
12/7:24/5=1/7:2/5=5:14
12:5/4=48:5
24:72=1:3
1.6:6.4=1:4
7/2:5/3=21:10

12 to 24 to 32

12:24:32 divided by 4
=3：6：8