There are two resistors, a and B, which are connected in series to a certain circuit. It is measured that the ratio of electric power consumed by them is 3:2. If they are connected in parallel to the same circuit The ratio of electric power consumed by them is as follows:

There are two resistors, a and B, which are connected in series to a certain circuit. It is measured that the ratio of electric power consumed by them is 3:2. If they are connected in parallel to the same circuit The ratio of electric power consumed by them is as follows:

First of all, the series connection is divided into voltage and the current is equal. From the formula P = the square of the current multiplied by the resistance, R1: R2 = 3:2
In parallel circuit, the voltage is equal and the current is divided, so from the perspective of voltage, the formula P = the square of voltage divided by the resistance is P3: P4 = 2:3, so the answer is 2:3

If resistance B is connected to another circuit separately, it is known that the voltage at both ends of the power supply of the later circuit is twice that of the original circuit, then the power consumed by resistance B in the later circuit is P2 ′ =___ ．

∵ two resistors A and B are connected in series, and the voltage at both ends of the original circuit power supply is u, ∵ P = P1 + P2, I = Pu = P1 + P2u, R2 = p2i2 = P2 (P1 + & nbsp; P2u) 2 = p2u2 (P1 + P2) & nbsp; & nbsp; 2, ∵ the voltage at both ends of the original circuit power supply is u, ∵ later, the voltage at both ends of the circuit power supply is 2U, P2 ′ = (2U) 2r2 = 4u2p2u2u2 (P1 + P2) & nbsp