How much electricity does a refrigerator, a computer, a water heater and an air conditioner need 24 hours a day? Just about one,

How much electricity does a refrigerator, a computer, a water heater and an air conditioner need 24 hours a day? Just about one,

Refrigerator is about 110W, about 1 degree every day;
Computer is generally about 300W, about 7 degrees a day;
If the air conditioner is 1p, it is about 730W, about 12 degrees a day;
Total: about 20 degrees. (this is a big approximation, because the power has a great relationship)
If it is an electric water heater, the power difference is too big, from 2000 to 7000W, and the use time is very critical, so it is inconvenient to calculate

One 220 V 40 W fluorescent lamp, two 220 V 8 W fluorescent lamps, one 220 V 60 W television, one 220 V 130 w refrigerator and one 220 V 350 W washing machine are used at the same time. What is the total current in the circuit?
One 220 V 40 W fluorescent lamp, two 220 V 8 W fluorescent lamps, one 220 V 60 W TV, one 220 V 130 w refrigerator and one 220 V 350 W washing machine are used at the same time. What is the total current in the circuit

At the same time, the total power of the circuit is p = 40 + 8x2 + 60 + 130 + 350 = 596w
At the same time, the consumers in the circuit are in parallel, u = 220 v
At the same time, the total current I = P / u = 2.71a

A classmate has a TV, a refrigerator, a fluorescent lamp and an electric fan
Their normal working currents are 180 Ma, 1.2 A, 120 mA and 320 Ma respectively, and the total charge passing through the circuit in one hour is calculated

(0.18 + 1.2 + 0.12 + 0.32) * 3600 = 1.82 * 3600 = 6552 Coulomb

A classmate has a TV set, a refrigerator, a fluorescent lamp and an electric fan in his home. Their current wind is 180mA 1.5A 120mA 320
A classmate has a TV set, a refrigerator, a fluorescent lamp and an electric fan in his home. When they work, the current is 180mA, 1.5A, 120mA and 320mA respectively. When they work, what is the current of the trunk road

The main circuit current is equal to the sum of the branch currents
0.18+1.5+0.12+0.32=2.12A
In the process of calculation, Ma is changed into a and then added