If the perimeter of a rectangle is 38cm and the length is 1cm more than the width, the length of the rectangle is______ cm．

Let the width be xcm, then the length be (x + 1) cm. According to the equation, we get: (x + 1 + x) × 2 = 38, and the solution is x = 9. The length of the rectangle is x + 1 = 9 + 1 = 10, so the answer is 10

There are two rectangles, the ratio of length to width of the first rectangle is 5:4, the ratio of length to width of the second rectangle is 3:2, the perimeter of the first rectangle is 112 cm larger than that of the second rectangle, and the width of the first rectangle is 6 cm larger than that of the second rectangle, so the area of the two rectangles can be calculated

Let the length and width of the first rectangle be 5xcm and 4xcm respectively, and the length and width of the second rectangle be 3ycm and 2ycm respectively. According to the meaning of the title, we get 2 × (5x + 4x) − 2 × (3Y + 2Y) = 1124x = 2 × 3Y + 6, and the solution is x = 9y = 5. Thus, the area of the first rectangle is: 5x × 4x = 20x2 = 1620 (cm2); the area of the second rectangle is: 3Y × 2Y = 6y2 = 150 (cm2). A: the area of the two rectangles is divided into two parts 1620 cm 2 and 150 cm 2, respectively

As shown in the figure: the circumference of the rectangle is 38 cm, and the shadow is a square

Let the side length of a square be x, then 4x + 5 × 2 = 38 & nbsp; & nbsp; & nbsp; & nbsp; 4x + 10 = 38 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 4x = 28 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 7; 7 + 5 = 12 (CM) a: the length of a rectangle is 12 cm, the width is 7 cm

The perimeter of an equilateral triangle is 15.6cm, 7cm. How many square centimeters is its area?

15.6 △ 3 = 5.2 cm (side length)
5.2 × 2.7 ÷ 2
= 14.04 ÷ 2
=7.02 square centimeter
A: its area is 7.02 square centimeters

If the perimeter of a rectangle is 38cm and the length is 1cm more than the width, the length of the rectangle is______ cm．