The minimum natural number that can be divisible by 225 is 0, 1 or 2______ ．

The minimum natural number that can be divisible by 225 is 0, 1 or 2______ ．

225 = 3 × 3 × 5 × 5 = 9 × 25. If a number can be divided by 9 and 25 at the same time, the number can be divided by 225. If the number can be divided by 25, the last two digits must be 00, 25, 50 or 75 (because the topic requires 012, there is only 00); if the number is divided by 9, the sum of each digit can be divided by 9; therefore, the minimum natural number that meets the conditions is 1222200; so the answer is 1222200

In the decimal system, each digit is 0 or 1 and can be divided by 225. What is the minimum natural number?
Make it clear!

First of all, the number of 225 bits is 5, so 225 times odd number bits is 5, which is not suitable. 225 times even number is 0, so the lowest point must be 0. Because 225 contains a prime factor of 9, it can be divisible by 225 and 9. The number divisible by 9 has one characteristic: the sum of all numbers on you can be divisible by 9

The minimum natural number that can be divisible by 225 is 0, 1 or 2______ ．

225 = 3 × 3 × 5 × 5 = 9 × 25. If a number can be divided by 9 and 25 at the same time, the number can be divided by 225. If the number can be divided by 25, the last two digits must be 00, 25, 50 or 75 (because the topic requires 012, there is only 00); if the number is divided by 9, the sum of each digit can be divided by 9; therefore, the minimum natural number that meets the conditions is 1222200; so the answer is 1222200

1-1998 the sum of all the numbers in these natural numbers can be divided by 5
How many of these natural numbers can be divided by 5?

One digit is 5 two digits 18 ten digits 1-9 digits 0-99 * 10 / 10 * 2 = 18 algorithm: 9 stands for ten digits 9 cases 10 stands for ten digits 10 cases 10 stands for ten digits 2 stands for two of these ten digits can divide 5 example: ten digits is ten digits of 1, you add up to ten