Proof: if the sum of four digits of four digits can be divided by 9, then the four digits can also be divided by 9 Thank you for another question, which is 9x ^ 4 + 12x ^ 3-3x ^ 2-7x + 2010

Proof: if the sum of four digits of four digits can be divided by 9, then the four digits can also be divided by 9 Thank you for another question, which is 9x ^ 4 + 12x ^ 3-3x ^ 2-7x + 2010

A three digit number is not only a multiple of 12, but also a multiple of 5, and 9 is its factor. What is the largest of the three digits______ ．

12 × 5 × 9 = 540, a: the maximum of this three digit number is 540

There are three consecutive two digit natural numbers, the sum of which is also a two digit natural number, and the sum is a multiple of 23______ ，______ ，______ ．

The sum of three consecutive two digit numbers must be a multiple of 3. It is known that the sum is a multiple of 23, and 3 and 23 are coprime, so the sum is a multiple of (3 × 23) = 69. There is only one two digit number divisible by 69, they are 69. So the three numbers are 22, 23, 24; so the answer is: 22, 23, 24

Why can integers whose sum of numbers is a multiple of 3 be divided by 3

If it's a three digit number, the order is a B C
100A + 10B + C = 99A + 9b + A + B + C see