The polar coordinate equation of curve C is ρ = 4cos θ. The abscissa of curve C is shortened to the original one, and then shifted one unit to the left, How can we get 4x Λ 2 + y Λ 2 = 4 The abscissa of curve C is shortened to 1 / 2 of the original

The polar coordinate equation of curve C is ρ = 4cos θ. The abscissa of curve C is shortened to the original one, and then shifted one unit to the left, How can we get 4x Λ 2 + y Λ 2 = 4 The abscissa of curve C is shortened to 1 / 2 of the original


Multiply ρ on both sides
ρ²=4ρcosθ
x²+y²=4x
So it should be (X-2) &# 178; + Y & # 178; = 4
The abscissa is reduced to half of the original
X becomes 1 / 2 = 2
(2x-2)²+y²=4
Shift 1 unit to the left
X becomes x + 1
So 4x & # 178; + Y & # 178; = 4



Given the polar coordinate equation P = 4cos θ / 1-cos2 θ of conic C C, the rectangular coordinate equation of conic C C is obtained


p=4cosθ/(1-cos2θ)=4cosθ/(2sin^2 θ)=2cosθ/(sinθ)^2
p(sinθ)^2=2cosθ
(psinθ)^2=2pcosθ
By substituting x = PCOS θ, y = PSIN θ
y^2=2x



A point on the number axis moves 4 units each time from the origin. What is the number represented by the position where it moves three times?


There are four answers - 4, 4, - 12, 12
I don't know, right



On the number axis, the point AB represents the rational number AB respectively, and the origin 0 is just the midpoint of ab. find the value of 1 / 2 of 2005a × 5B


The point AB represents the rational number AB respectively, and the origin 0 is just the midpoint of ab
AB is the opposite number, B = - A
2005a×1/5b=-401



(1) On the number axis, points a and B represent rational numbers a and B respectively, and the origin 0 is just the midpoint of ab. find the value of one-third of 2005 ax5b
(2) If | x-3 | + | y + 2 | + | 2Z + 1 | = 0, find the value of (XY YZ) × (Y-X + Z)


(1).401*(-1)=-401
(2).x=3 y=-2 z==-0.5
[3*(-2)-(-2)*(-0.5)]*[(-2)-3+(-0.5)]
=-5*(-5.5)
=27.5



Given that | a | = 4, | B | = 6, | C | = 8, and the positions of rational numbers a, B, C on the number axis are shown in the figure, find the value of 4 (a + b) + 4 (A-C) - 2 (B-C)


According to the meaning of the question: a = 4, B = 6, C = - 8, then the original formula = 4A + 4B + 4a-4c-2b + 2C = 8A + 2b-2c = 32 + 12 + 16 = 60



On the number axis, point a represents + 2. From point a to point B, move 4 unit lengths to the left along the number axis. What is the rational number represented by B? If you move one unit length to the right from point B to point C, what is the rational number represented by point C?


∵ + 2 + (- 4) = - 2, the rational number represented by B is - 2, ∵ - 2 + (+ 1) = - 1, and the rational number represented by C is - 1



1、 Multiple choice questions: 1. Given that three points a, B and C on the number axis represent rational numbers, 1 and - 1 respectively, then represent the distance between (a) a and B(
Seeking answers


Is there a mistake in this question? Why is there only one choice



The corresponding points of rational numbers a, B and C on the number axis are shown in the figure, and | a | > | B|
————a——c——0———b
|a-b|=
|a+b|=
|a+c|=
|b-c|=


|a-b|=b-a
|a+b|=-a-b
|a+c|=-a-c
|b-c|=b-c



If the real numbers a and B are represented on the number axis as shown in the figure, the following conclusion is wrong ()
A. a+b<0B. ab<0C. -b>aD. a-b<0


According to the number axis, we can get B < - 1 < 0 < a < 1, a, a + B < 0, so option a is correct; B, ab < 0, so option B is correct; C, - B > a, so option C is correct; D, A-B > 0, so option D is wrong