A school organized 304 teachers and students to carry out long-distance inspection activities, with 260 pieces of luggage. It plans to rent two types of cars: A and B. It is understood that a car is not available Car a can carry 40 people and 16 pieces of luggage, car B can carry 30 people and 20 pieces of luggage. In order to make all cars just right, how many cars of two models should be rented

A school organized 304 teachers and students to carry out long-distance inspection activities, with 260 pieces of luggage. It plans to rent two types of cars: A and B. It is understood that a car is not available Car a can carry 40 people and 16 pieces of luggage, car B can carry 30 people and 20 pieces of luggage. In order to make all cars just right, how many cars of two models should be rented

Car a and car B can be loaded 10 times, so 304 people will have at least 4 people free no matter what, so the problem is wrong

A school is going to organize 290 students to carry out field investigation activities. There are 100 pieces of luggage. The school plans to rent a and B two types of cars, a total of 8, a can carry 40 people and 1
Luggage B 30 people and 20 pieces of luggage design all possible car rental programs

With a car x, there are B car (8-x)
40x+30(8-x)≥290①
10x + 20 (8-x) ≥ 100 (I think your condition is wrong, car a should be able to carry 10 pieces of luggage, otherwise there is no solution)
The solution is: X ≥ 5
Solution 2: X ≤ 6
∵ x takes an integer
∴x=5、6
A: you can rent 5 cars a and 3 cars B, 6 cars a and 2 cars B

360 teachers and students went to visit. If we rent a number of buses just full, if we rent B type buses, we can rent one less and the remaining 40 seats,
A school organized 360 teachers and students to visit. If a number of class a buses are just full; if B buses are rented, one can be rented less, and there are 40 seats left. It is known that a bus has 20 seats less than B buses. How many class a buses and B buses can be rented separately

If car a can take x people, then car B can take (x + 20) people. If you rent n cars of car a, then you only need (n-1) cars of car B. then the following equation can be formulated: ① 360 / x = n; ② (360 + 40) / (x + 20) = (n-1). By synthesizing ① and ②, you can get x ^ 2 + 60x-7200 = 0. By solving this equation, you can get X1 = 60, X2 = - 120

A school organized 360 teachers and students to visit the construction of the Three Gorges Project. If a number of class a buses are just full, and if a number of class B buses are rented, one can be rented less, and there are 40 empty seats left. (1) it is known that class a buses have 20 seats less than class B buses, so how many seats each class A and class B buses have; (2) it is known that the rent of class a buses is 400 yuan, and that of class B buses is 480 yuan The two kinds of buses are rented at the same time during this visit. One of them is less than the other. The rent is less than that of any other bus. How much is the rent required according to this plan?

(1) Let a bus have X seats, then B bus has (x + 20) seats. According to the meaning of the question, we get 360x = 360 + 40x + 20 + 1. After sorting out, we get x2 + 60x-7200 = 0, the solution is X1 = 60, X2 = - 120 (not the meaning of the question, omit) ‖ x = 60. After testing, x = 60 is the solution of the original fractional equation, and conforms to the meaning of the question, then x + 20 = 80