A certain engineering team needs to recruit 150 workers of both types of work. The monthly salary of workers of both types of work is 800 yuan / person and 1200 yuan / person respectively. Now the number of workers of type B is required to be no less than twice of that of type A. Q: how many workers of both types of work can make the minimum monthly salary and the minimum total salary

A certain engineering team needs to recruit 150 workers of both types of work. The monthly salary of workers of both types of work is 800 yuan / person and 1200 yuan / person respectively. Now the number of workers of type B is required to be no less than twice of that of type A. Q: how many workers of both types of work can make the minimum monthly salary and the minimum total salary

Suppose that workers of type A should recruit x people, and workers of type B should recruit (150-x) people. The monthly salary of X workers of type A is 800X yuan, and that of (150-x) workers of type B is 1200 yuan. According to the meaning of the question, a set of inequalities can be listed: 150-x ≥ 2XX ＞ 0x ＜ 150

There are 1200 workers in the two workshops. After 1 / 5 of the workers in workshop a are transferred to workshop B, the number ratio of workshop a and workshop B is 5:7?

Suppose there were x people in a, then there were 1200-x people in B
(x-1/5x)：(1200-x+1/5x)=5:7
That is, 4 / 5x: (1200-4 / 5x) = 5:7
28/5x=6000-4x
48/5x=6000
x=625
Then B has 1200-625 = 575
A
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If an engineering team wants to recruit 150 workers of type A and type B, it should pay 800 yuan and 1200 yuan to the workers of type A and type B respectively. However, the project requires that the number of workers of type B should not be less than twice that of type A. Q: how many workers of type A and type B can be recruited to minimize the monthly wage and calculate the minimum total wage
The best is inequality

The whole process of this problem is as follows:
If an engineering team wants to recruit 150 workers of type A and type B, it should pay 800 yuan and 1200 yuan to the workers of type A and type B respectively. However, the project requires that the number of workers of type B should not be less than twice that of type A. Q: how many workers of type A and type B can be recruited to minimize the monthly wage and calculate the minimum total wage
According to the meaning of the question, we can get the following results:
150-x≥2x
The solution is x ≤ 50
If you pay y yuan per month, you can get
y=800x+1200(150-x)
=-400x+180000
The larger x is, the smaller y is
Substituting x = 50 into y = - 400X + 180000
Y = 178000
∴150-x=100
A: when 50 people are recruited for type A and 100 people are recruited for type B, the minimum monthly salary is 178000 yuan
This problem mainly uses the knowledge of inequality and linear function, many of the most valuable problems can be solved by this method

There are 306 students in a school. If the number of boys increases by 2 / 35 and the number of girls decreases by 2, the total number of students will increase by 6

(2 + 6) × 35 / 2 = 140 there were 140 boys in the school

There are several students in a school. The number of boys is 62 more than two-thirds of the total number of the school. The number of girls is 20 less than one-fifth of the total number of the school
There are several students in a school. The number of boys is 62 more than two-thirds of the total number of the school, and the number of girls is 20 less than one-fifth of the total number of the school. How many boys and girls are there in the school?

Whole school: (62-20) / (1-2 / 3-1 / 5) = 315 (persons)
Male: 315 × 2 / 3 + 62 = 272
Female: 315 × 1 / 5-20 = 43

The number of male students in a school is 60 more than three fifths of the total number of the school, and the number of female students is one third of the number of male students. How many students are there in this school?

300 people

There are 27 girls and 28 boys in class 6 (1). Class 6 (1) accounts for five ninth of the total number of students in the whole grade. How many students are there in the whole grade

99. (28 + 27) / (5 / 9) = 99

During the May Day holiday, a tour group composed of four teachers and several students in a school
During the May Day holiday, a tour group composed of four teachers and several students from a certain school planned to travel to a certain place and selected two travel agencies. The charge standard of travel agency a is: if you buy four full tickets, the rest of the people will get a discount of 70%. The charge standard of travel agency B is: more than five people (including five people) can buy group tickets, and all people will get a discount of 20% of the original price, The full fare of the two travel agencies is 100 yuan per person
(1) If there are 10 students participating in the tour, which travel agency is more economical?
(2) When the number of students participating in the tour group is within what range, it is more economical to choose B travel agency?
Note: use inequality!

(1) A: 4x100 + (10-4) x100x0.7 = 820 (yuan) B: 10 > 5 10x100x0.8 = 800 (yuan) 820 > 800, so it is more economical to choose B travel agency. (2) when the number of tourists is 1 ~ 4, the price of B travel agency is the same; when the number of tourists is 1 ~ 4, set n number B

During the National Day golden week of the 11th National Day, the school's tour group composed of four teachers and some students wants to travel to scenic spots. The charge standard of travel agency a is: group tickets for more than five people (including five people) are 20% off the original price; the charge standard of travel agency B is: if you buy four full tickets, the rest will be 70% off, and the full ticket price of the two travel agencies is 300 yuan
(1) If there are ten students participating in the tour, which one is more economical?
(2) When the number of participants is how many, the two charge the same amount?

Charge of Party A:
Total number 14 * group ticket 20% discount 240 yuan = 3360 yuan
Party B's charge:
4 people * 300 full vote = 1200 yuan
10 people * 70% discount ticket 210 yuan = 2100 yuan
1200 + 2100 = 3300 yuan
To sum up, a travel agency charges 60 yuan more than B travel agency

There was a group of 50 people who stayed in a hotel
There is a tour group of 50 people who stay in a hotel. There are three kinds of rooms in the hotel, including three rooms, two rooms and single rooms, of which three rooms are 20 yuan per day, two rooms are 30 yuan per day and single room is 50 yuan per day. If the tour group has a total of 20 rooms, how to arrange the lowest cost of accommodation?
Let two kinds of unknowns --
Don't set three unknowns

Suppose three room x double room y single room 20-x-y 3x + 2Y + 20-x-y = 50, then y = 30-2x accommodation cost = 3x * 20 + 2Y * 30 + (20-x-y) * 50 = 10x + 10Y + 1000, substituting y = 30-2x into the above formula, we can get 10x + 10 * (30-2x) + 1000 = 1300-10x, from 30-2x = Y > = 0, we can get X