A and B set out from a and B at the same time, facing each other. When they set out, their speed ratio was 3:2. After the first meeting, a's speed increased by 15, B's speed increased by 310. In this way, when a arrives at B, B is still 14 kilometers away from a, so what's the distance between a and B?

A and B set out from a and B at the same time, facing each other. When they set out, their speed ratio was 3:2. After the first meeting, a's speed increased by 15, B's speed increased by 310. In this way, when a arrives at B, B is still 14 kilometers away from a, so what's the distance between a and B?

Before meeting, the speed ratio of a and B is 3:2, so when meeting, a takes 35 times of the whole course, and B takes 25 times of the whole course. After meeting, the speed ratio of a and B is (3 × 65): (2 × 1310) = 185:135 = 18:13, 14 △ (35 − 25 × 1318) = 14 ^ (35 − 1345) = 14 ^ △ 1445 = 14 × 4514 = 45 (km). A: the distance between a and B is 45 km

Party A and Party B are walking from ab at the same time. The first time they meet is 700 meters away from a, then they meet and continue to move forward. When they arrive, they return immediately. The second time they meet is 400 meters away from B, so as to find the distance between two places

The first meeting, a line 700 meters
For the second meeting, the first line is 700 * 3 = 2100 meters or more than 400 meters in a whole journey
So AB distance is 2100-400 = 1700m
A: the distance between the two places is 1700 meters

Party A and Party B set out from ab at the same time, facing each other. When they first met head-on, they were 50 meters away from A. after meeting, they continued to move forward
When people arrive at their destination, they all return immediately. When they meet 20 meters away from B for the second time, what is the distance between the fourth meeting place and a?

From the start to the first face-to-face meeting, Party A and Party B walked a whole journey, and Party A walked 50 meters
From the start to the second face-to-face meeting, Party A and Party B walked a total of 3 whole courses, and Party A walked 50 * 3 = 150 meters [1 whole course + 20 meters]
1 whole course = 150-20 = 130m
From the start to the fourth face-to-face meeting, Party A and Party B walked a total of 7 whole courses, and Party A walked 50 * 7 = 350 meters
350 / 130 = 2 whole journey ······· 90m
A: the distance between the fourth meeting place and a is 90 meters

Party A and Party B are facing each other from ab. the first time they meet is 700 meters away from a, and then they go on. A goes back to B, B goes back to a, the second time they meet is 400 meters away from B, and then they go on. A goes back to a, B goes back to B, and the third time they meet, how many meters away from a?

Set the whole distance to x km
The distance of each encounter is x, and a passes 700 meters
The total distance of each second encounter is 3x, and a passes x + 400m
The time ratio is 1:3
Set the time as s and 3S respectively
700S=(X+400)/3S
X=1700
The whole course is 1700 meters
A s time passes 700 meters
The third meeting, after 5S
A: 700 * 5 = 3500 meters
3500/1700=2…… one hundred
The third meeting, 100 meters away from a point