The two trains of a and B leave each other from station AB at the same time. After meeting 60 kilometers away from station a, the two trains continue to move forward at the same speed, return immediately after arriving at the other's starting place, and meet again 30 kilometers away from station B

The two trains of a and B leave each other from station AB at the same time. After meeting 60 kilometers away from station a, the two trains continue to move forward at the same speed, return immediately after arriving at the other's starting place, and meet again 30 kilometers away from station B

Let AB long x a speed be V1, B speed be V2, and the time of two encounters be T1, T2 respectively. The following equation can be listed from the Title Meaning: v1t1 = 60v2t1 = x-60v1 / V2 = 60 / (X-60) at the first encounter; v1t2 = x + 30v2t2 = 2x-30v1 / V2 = (x + 30) / (2x-30) at the second encounter

The two trains of a and B leave each other from station AB at the same time. After meeting 60 kilometers away from station a, the two trains still advance at the same speed, and each train arrives at the other side respectively
Return immediately after the starting point, and meet at the place 80 km away from station A. how many kilometers is the distance between station AB and station a

(60 × 3 + 80) △ 2 = 130 km
The distance between the two stations is 130 km

A and B trains leave from station a and B at the same time. When they meet 60 km away from station a, they continue to move forward at the same speed. When each train arrives at the other's starting point, they return immediately. When they meet 30 km away from station B, a and B are separated_________ Kilometers

(s-60)/60=[60+(s-30)]/[(s-60)+30)]
The results are as follows
(s-60)/60=(s+30)/(s-30)
Solving the equation, s = 0, s = 150
The blank should be filled in 150

A's speed is twice as fast as B's. they start from a and B respectively and face each other. One hour later, they meet at a distance of 3km from the destination. After meeting, they continue to move forward
When a arrives at B, B is still? Km away from a

Suppose a is n times as big as B
One hour later, they were 3 kilometers away from the destination. A was faster than B, which means 3 kilometers away from B
B walked 3 kilometers, then a walked 3N kilometers
It takes an hour for B to walk three kilometers, and an hour for a to walk the last three kilometers
Then B walked 1 / N kilometer after meeting
Distance from point A: 3n-1 / n km
Exactly how many times, you take n in