Eight people take two cars with the same speed to the railway station at the same time, and each car takes four people (excluding the driver) One of the cars broke down 10km away from the railway station, and there was still 40 minutes to stop checking in. At this time, the only available means of transportation was another car. It was known that the car, including the driver, was limited to five people, and the average speed of the car was 40km / h. The average walking speed of people was 4km / h, The calculation shows that these 8 people can get to the railway station before stopping checking in

Eight people take two cars with the same speed to the railway station at the same time, and each car takes four people (excluding the driver) One of the cars broke down 10km away from the railway station, and there was still 40 minutes to stop checking in. At this time, the only available means of transportation was another car. It was known that the car, including the driver, was limited to five people, and the average speed of the car was 40km / h. The average walking speed of people was 4km / h, The calculation shows that these 8 people can get to the railway station before stopping checking in


If the first group of four people take the bus for X hours, the distance between the place of getting off and the destination is (10-40x) km. By this time, the second group of four people have walked for 4x km
The time when they met the returning car was (40x-4x) / (40 + 4) = 9 / 11x hours, during which the car drove 9 / 11x × 40
=The distance between the bus and the railway station is [360x △ 11 + (10-40x)] km. The bus and the first group of people arrive at the railway station at the same time
The time taken (calculated from the time when the first group of people get off the bus) is equal
9X÷11+【360X÷11+(10-40X)】÷40=(10-40X)÷4
The solution is x = 11 / 52 hours
So when sharing: 11 △ 52 + [10-40 × (11 / 52)] 4 = 31 / 52 (hours) ≈ 35.8 (minutes)



There are eight people going to the railway station at the same time in two cars with the same speed, each car takes four people (excluding the driver)
When the two cars are 10 kilometers away from the station, one car breaks down and there are 40 minutes to check in. The speed of the car is 40 and the walking time is 4


Assuming that the starting point is a and the ending point is D, the optimal delivery method is: the car first sends a group of people (assuming the first group) to C, and at the same time another group of people (assuming the second group) walks forward. When the car reaches C, the car comes back to pick up the second group of people, and meets with B, and the second group of people walks to the end. When two groups of people reach the end at the same time, it should be the most ideal, L3 then when the car and the second group of people meet at point B, they will meet (the same time): (L1 + 2 * L2) / 40 = L1 / 4l2 = 4.5l1, the first group of people and the second group of people will arrive at the destination at the same time: (2 * L2 + L3) / 40 = L3 / 4l2 = 4.5l3, and the total distance is 10, so we can calculate L1 = 20 / 13; L2 = 90 / 13; L3 = 20 / 13; therefore, the total time can be calculated by the time spent by the first group of people (or the second group of people): T = L1 / 4 + (L2 + L3) / 40 = 31 / 52 (hours)



Eight people take two cars with the same speed to the railway station at the same time, and each car takes four people (excluding the driver). One of the cars breaks down 10 kilometers away from the railway station, and there is still 28 minutes to stop checking tickets. At this time, the only available means of transportation is another car. It is known that this car, including the driver, is limited to five people, and the average number of passengers of this car is 5 The speed is 60 km / h, and the average walking speed is 5 km / h. (1) when the car breaks down, four people in this car get out of the car and walk. Another car takes the four people in the car to the railway station, and immediately returns to the station. How many kilometers is the walking distance? How many minutes does it take for all eight people to get to the railway station? (2) Another plan is designed, which shows that the eight people can get to the railway station before stopping checking


(1) Suppose that the walking distance of four people taking the faulty car is x km, according to the meaning of the question, there is, X5 = 10 + 10-x60, the solution is: x = 2013, the time required for all the eight people to arrive at the railway station is 2013 △ 5 + (10-2013) △ 60 = 3578 (hours) = 261213 (minutes); answer: the walking distance of four people is 2013 km, the time required for all the eight people to arrive at the railway station is 261213 minutes; (2) when the bus stops, it will take a lot of time When the car breaks down, four people in this car will get off and walk. Another car will send the four people in the car to a certain place, let them get off and walk, and then immediately return to the other four people who pick up the faulty car and walk, so that the two groups of people finally arrive at the station at the same time. The walking distance of the two groups of people is the same, as shown in the figure, D is the place where the trouble free car personnel get off, C is the trouble free car personnel Therefore, let AC = DB = y, according to the meaning of the question, there is: Y5 = 10-y + 10-2y60, the solution is: y = 43, so the time for these eight people to arrive at the railway station at the same time is 43 △ 5 + (10-43) △ 60 = 3790 (hours) = 2423 (minutes) ≈ 24.67 < 28, so this scheme is feasible



Eight people take two cars with the same speed to the railway station at the same time, and each car takes four people (excluding the driver). One of the cars breaks down 15 km away from the railway station, and there is still 42 minutes to stop checking tickets. At this time, the only available means of transportation is another car. It is known that this car, including the driver, can only take five people, and the average speed of this car is 60 km /h. The average speed of walking is 5km / h. two different schemes are designed, and the calculation shows that the eight people can get to the railway station before stopping checking in. (1) scheme 1: (2) scheme 2: (1) scheme 2: (2) scheme 3: (2) scheme 3: (2) scheme 3: (2) scheme 3: (2) scheme 3: (2) scheme 3: (2) scheme 3: (2) scheme 3: (2) scheme 3: (


To catch up with the train, there are two feasible solutions: 1. When the car delivers the first four people, the rest of the people walk forward at the same time. When the car arrives at the railway station, it returns to pick up the rest of the people