When someone runs along the sidewalk on the road, he observes that every 15 minutes a bus comes from behind: every 10 minutes a bus comes from the opposite side. If the speed of the person and the bus remains the same, then every few minutes a bus starts from the station?

12 minutes
If the distance between the two stations is l, the speed is a, and the speed is B, then we can know
1) L / (a + b) = 10 minutes,
2) L / (a-b) = 15 minutes,
It can be inferred
3）a=5b,
And then we're going to figure out what l / a = is,
That is, by bringing 3) into 1), we can know that l / 1.2A = 10, then l / a = 12 minutes
8 A = 15, then l / a = 12 minutes

Xiao Ming walks home along a highway after school. Every 10 minutes, a bus overtakes him from behind. Every 6 minutes, he meets a bus coming face to face. How many buses are there

The distance between the two cars is constant, set as S
Xiaoming's speed is V1 and the car's speed is v2
S/(V1+V2)=6
S/(V2-V1)=10
In contrast, V2 = 4v1, s = 30v1
How many minutes apart is required to send a car, which can be understood as the time t for Xiaoming to walk from one car to another
T=S/V1
We can get t = 30
A: every 30 minutes

The speed ratio of a and B is 7:8. How much less does a run than B in 10 minutes?

12.5 percent

When someone runs along the sidewalk on the road, he observes that every 15 minutes a bus comes from behind: every 10 minutes a bus comes from the opposite side. If the speed of the person and the bus remains the same, then every few minutes a bus starts from the station?