Car a and car B travel from two places at the same time. They meet in 2.5 hours. It is known that car a's speed is 3 / 4 of car B's. when they meet, car B walks 40 kilometers more than car a Ask for the speed of a and B cars. It's urgent to hand it in on Thursday. There should be analysis and process, not just the answer

Car a and car B travel from two places at the same time. They meet in 2.5 hours. It is known that car a's speed is 3 / 4 of car B's. when they meet, car B walks 40 kilometers more than car a Ask for the speed of a and B cars. It's urgent to hand it in on Thursday. There should be analysis and process, not just the answer

The speed ratio of a and B is 3 / 4:1 = 3:4
Then the travel ratio of Party A and Party B is 3:4
When they met, a traveled 40 / (4-3) * 3 = 120 km. B traveled 40 / (4-3) * 4 = 160 km
Therefore, a speed = 120 / 2.5 = 48 km / h
B speed = 160 / 2.5 = 64 km / h

The express train runs from station a to station B at the speed of 60 km / h. after 1.5 hours, the slow train runs from station B to station a at the speed of 40 km / h. When the two trains meet, the meeting point is 70 km away from the midpoint of the two stations. How many kilometers are there between station a and station B?

According to the meaning of the question: when driving at the same time, the distance of the fast train is more than that of the slow train: 70 × 2-60 × 1.5 = 140-90 = 50 (km); the travel time of the two trains is: 50 △ 60-40 = 50 △ 20 = 2.5 (H); so the total distance between the two places is: 60 × 1.5 + (60 + 40) × 2.5 = 90 + 100 × 2.5 = 90 + 250 = 340 (km)