It takes 5 hours and 30 minutes for a plane to travel between the two cities in the downwind and 6 hours in the upwind. The known wind speed is 24 kilometers per hour, so the distance between the two cities can be calculated

It takes 5 hours and 30 minutes for a plane to travel between the two cities in the downwind and 6 hours in the upwind. The known wind speed is 24 kilometers per hour, so the distance between the two cities can be calculated

Let the distance between the two cities be x km. From the meaning of the title, we can get x 512-x6 = 24 × 2. The solution is x = 3168. A: the distance between the two cities is 3168 km

How to do the mathematical problem of plane navigation
When a plane flies between two cities, it takes 2 hours and 50 minutes to go downwind and 3 hours to go upwind. The known wind speed is 20km / h. how long is the distance between the two cities?

Let the plane fly x kilometers per hour, and the distance between the two cities is y kilometers
therefore
y=(x+20)*17/6=(x-20)*3
If you solve this equation, you will have
x=700
y=2040
So the distance between the two places is 2040 km

There are 10 planes in the airport. After the first plane takes off, one plane takes off every four minutes, and two minutes after the first plane takes off
Another plane landed at the airport, and then one plane landed at the airport every 6 minutes, and the plane landed at the airport took off after the original 10 planes every 4 minutes. Then, after taking off from the first plane, how long did it take, and how many planes did not stay at the airport for the first time?

Suppose that the time from the first plane to the last plane landing on the airport is X minutes, then in X minutes, the number of planes taking off is x / 4 + 1, and the number of planes landing is [(X-2) / 6] + 1. Therefore, the number of planes decreasing on the Airport is:
　　（X/4+1）-【（X-2）/6】+1=9
X = 104 means that in 104 minutes, each plane takes off and lands. At this time, the number of planes in the airport is 1. After 4 minutes, this plane takes off. During this period, no plane lands and there is no plane in the airport. Therefore, from the first plane takes off to 108 minutes, there is no plane in the airport
Solution 2: let the time from the first plane take off to the last plane take off be X minutes. During this period, a total of X / 4 + 1 plane takes off, and at the same time [(x-2-4) / 6] + 1 plane lands
　　（X/4+1）-【（ X-2-4）/6+1】=10
The solution of the equation is x = 108, that is, there will be no aircraft in the airport in 108 minutes
Solution 3: the time from the first plane taking off to the last plane taking off must be divisible by 4 (one plane takes off every 4 minutes). Similarly, this time minus 2 and then minus 4 must be divisible by 6 (one plane lands every 6 minutes), so this time is the common multiple of 4 and 6. And [4,6] = 12,12 △ 4 = 3,12 △ 6 = 2, That is to say, every 12 minutes, there are three planes taking off and two planes landing at the airport. That is to say, every 12 minutes, there is one less plane at the airport. This process has been repeated nine times (from 10-3 + 2 = 9 to 2-3 + 1 = 0), so when there are no planes at the airport, it takes 12 × 9 = 108 minutes
Reference: Journey of the heart Sina blog

A plane flies 180 kilometers in 10 minutes. Its speed is several meters per second and how many kilometers per hour. It flies 30 seconds and the distance it passes is 100 kilometers
Shaomi

v=s/t=180000/600=300m/s=1080km/h
His speed is 300 meters per second and 1080 kilometers per hour
s=vt=9000m
It took 30 seconds to get through 9000m