As shown in the figure, after folding a rectangular piece of paper along EF, points D and C fall at d 'and C' respectively. If ∠ EFB = 65 °, what is ∠ AED? Don't copy. Don't Scribble

As shown in the figure, after folding a rectangular piece of paper along EF, points D and C fall at d 'and C' respectively. If ∠ EFB = 65 °, what is ∠ AED? Don't copy. Don't Scribble

The problem should be to find ∠ AED '
By folding, we can see ∠ def = ∠ d'ef
∵ AD‖BC
∴ ∠DEF=∠EFB=65°
∴ ∠DEF+∠D'EF=65°x 2= 130°
∴ ∠AED'=180°-- ∠DED'=180°-130°=50°

As shown in the figure, after folding a rectangular piece of paper along EF, points D and C fall at d 'and C' respectively. If ∠ EFB = 65 °, what is ∠ AED?

Because ed parallels BF
So ∠ EFB = ∠ def (two lines are parallel and the internal stagger angle is equal)
Because ∠ def = ∠ d'ef corresponds to equal angles and equal sides)
So ∠ d'ef = 60 degrees
Because ∠ d'ef + def + AED '= 180 degrees
So ∠ AED '= 180 degrees - (∠ d'ef + ∠ DEF) = 50 degrees

As shown in the figure, fold the rectangle ABCD along AE, if ∠ bad ′ = 30 °, then ∠ AED ′ = ()
A. 30°B. 45°C. 60°D. 75°

In the triangle AED ′, ∠ ead ′ = (90 ° - 30 °) △ 2 = 30 ° and ∠ D ′ = 90 °, so ∠ AED ′ = 180 ° - 90 ° - 30 ° = 60 °. Therefore, C