Find the rule again: 3 10 17————

Find the rule again: 3 10 17————

3 10 17 24 31 38 45
Each number is 7 times larger than the previous one

The examination questions for finding the law after primary school mathematics graduation: 2,3,4,5,6, (), () 1,2,3,5,8,13, (), () 2,4,6,8,10,12, (), () 1,3,5,7,9,1

The difference between 2,3,4,5,6, (7), (8) is 1
1,2,3,5,8,13, (21), (34) the latter is the sum of the first two terms
2,4,6,8,10,12, (14), (16) the difference is 2, even column
1,3,5,7,9, (11), (13) the difference is 2, odd sequence

The general formula of sequence 2,5,8,17,32,65

2+(2+1)=5
5+(4-1)=8
8+(8+1)=17
17+(16-1)=32
32+(32+1)=65
65+(64-1)=128
That is, an = a (n-1) + 2 ^ n - 1 ^ n
If you want to calculate all of them, you can sum the equal ratio sequence 2 ^ n

-7,7,11,17,19,21,23,29,… In the future, we will use the cycle of these 8 numbers to find the general term formula of this sequence?
Don't say I'm making questions, but it's useful

X(n)=X(n-8), X(0)=-7, X(1)=7, X(2)=11, X(3)=17, X(4)=19, X(5)=21, X(6)=23, X(7)=29