4 12 24 40 60 according to what rules

4 12 24 40 60 according to what rules

Law: 1 × 4,2 × 6,3 × 8,4 × 10,5 × 12
So: the nth term is n × (n + 1) × 2 = 2n (n + 1)

Find the rule 6 12 16 24 () ()

Find the rule 6 12 16 24 (30) (34) (42) (48)

225 × 265 × 262 × () make 4 zeros at the end and fill in the smallest number in brackets

The number of the following zeros depends on the multiplicity of the factors 2 and 5
It can be seen from the title that 225 × 265 × 262
The multiplicity of the first number 5 is 2
The multiplicity of the second number 5 is 1
The multiplicity of the third number 2 is 1
So that there are four zeros at the end of the product
It also needs to be 1 for multiplicity 5 and 3 for multiplicity 2
So 5 * 2 ^ 3 = 40
Minimum filling 40