Given that the rectangle ABCD, and ab = 5, ad = 3, establish an appropriate plane rectangular coordinate system, find the coordinates of each vertex of the rectangle

Given that the rectangle ABCD, and ab = 5, ad = 3, establish an appropriate plane rectangular coordinate system, find the coordinates of each vertex of the rectangle

Take a as the coordinate origin, AB as the X axis, ad as the Y axis
A（0,0）B(5,0) C（5,3) D(0,3)

In the plane rectangular coordinate system, the rectangle ABCD has a length of 8 and a width of 4. The length ab of the rectangle is on the x-axis and the width BC is on the y-axis?

D should have four coordinates, which are in the first, second, third and fourth quadrants respectively, and their coordinates are (8,4) (- 8,4) (- 8, - 4) (8, - 4)

In rectangular ABCD, ab = 4, BC = 3, if the rectangular ABCD is placed in the plane rectangular coordinate system, the point a coincides with the origin of the coordinate. AB forms an angle of 30 degrees with the positive direction of the x-axis, and B, C coordinates are obtained

B(2√3,2)
C(4√3-3/2,4-3√3/2)
perhaps
B(2√3,2)
C(4√3+3/2,4-3√3/2)
I hope that's right

Draw rectangle ABCD, make AB = 6, BC = 4, establish proper plane rectangular coordinate system in the plane of rectangle, and calculate the coordinates of points a, B, C, D respectively

Not even a certain store?

In rectangular coordinate system, the edge ab of rectangle ABCD can be expressed as (0, y) (- 1 ≤ y ≤ 2), and the edge BC can be expressed as (x, 2) (0 ≤ x ≤ 4)
(1) The coordinates of each vertex of a rectangle
(2) Circumference of rectangle ABCD
It's not a fixed value, is it

Your question is not very clear. So the answer is not so easy to say
(1) AB is expressed as (0, y) (- 1 ≤ y ≤ 2), which means that the X coordinates of a and B are 0, while the Y coordinates of a and B change from (- 1) to 2 respectively; edge BC is expressed as (x, 2) (0 ≤ x ≤ 4), which means that the X coordinates of B and C change from 0 to 4 respectively, while the Y coordinates are both 2
B: X = 0, - 1 ≤ y ≤ 2, and B: 0 ≤ x ≤ 4, y = 2, so the coordinate of B is: B (0,2)
A: X = 0, - 1 ≤ y ≤ 2 (because y = 2 at point B, y at point a cannot be equal to 2), that is, a (0, Y1) (- 1 ≤ Y1)

(1 / 2) in rectangular coordinates, the edge ab of rectangle ABCD can be expressed as (0, y) (- 1)

(1)
A(0,-1）,B(0,2）,C(4,2）,D(4,-1）
(2) Similarly, perimeter L = 2 * (AB + BC) = 2 * [(2-y1) + (x2-0)]
Perimeter of the largest rectangle: l = 2 * (AB + BC) = 2 * {[2 - (- 1)] + (4-0)} = 14

In rectangular coordinates, the edge ab of rectangle ABCD can be expressed as (2, y), (- 1)

The abscissa of ∵ ab ∥ Y axis and (2, y), (- 1 & lt; = y & lt; = 3) ∵ B is 2 ∵ BC ∥ X axis and the ordinate of (x, 3), (2 & lt; = x & lt; = 5) ∵ B is 3 ∵ B (2,3) ∵ the edge ab of rectangle ABCD can be expressed as (2, y), (- 1 & lt; = y & lt; = 3), and the edge BC can be expressed as (x, 3), (2 & lt; = x {%

The edges of rectangle ABCD are ab = 4, BC = 6. If the rectangle is placed in the rectangular coordinate system, and the coordinate of point a is (- 1,2), and AB / / X axis, try to find the coordinate of point C?

AB = 4, the coordinate of a is (- 1,2), and ab ∥ X axis, so the coordinate of B has two possibilities. One is on the left side of a, the coordinate is (- 1-4,2), that is (- 5,2). At this time, the coordinate of C also has two kinds, that is, the upper and lower coordinates of B are (- 5,2 ± 6), that is (- 5, - 4) and (- 5,8). The other is on the right side of a, the coordinate is (...)

As shown in the figure, in the plane rectangular coordinate system, the coordinates of vertex a of square ABCD are (0, 2), point B is on the x-axis, diagonal AC, BD intersect at point m, OM = 32, then the coordinates of point C are______ ．

Through point C, the CE ⊥ X axis is at point E, and through point m, the MF ⊥ X axis is at point F. the EM is connected with the quadrilateral ABCD as a square, am as cm, OAB as EBC, of = EF, MF as the median line of trapezoidal AOEC, and MF as 12 (AO + EC)

In the plane rectangular coordinate system, if the coordinates of three vertices of square ABCD are a (0,2), B (3,0), C (5,3), then the coordinates of vertex D are______ ．

As shown in the figure: ∵ square ABCD is an axisymmetric figure, a (0,2), B (3,0), C (5,3), and the coordinates of vertex D are (0 + 5-3 = 2,2 + 3-0 = 5), that is, (2,5). So the answer is (2,5)