In the known triangle ABC, ab = AC, the circle with ab as diameter intersects BC at D and AC at e, and BD = DC = De is proved In the known triangle ABC, ab = AC, the circle with ab as diameter intersects BC at D and AC at e, and BD = DC = De is proved

In the known triangle ABC, ab = AC, the circle with ab as diameter intersects BC at D and AC at e, and BD = DC = De is proved In the known triangle ABC, ab = AC, the circle with ab as diameter intersects BC at D and AC at e, and BD = DC = De is proved

Link ad;
AB is the diameter of a circle, so its corresponding circle angle ADB is a right angle, that is, ad ⊥ BC;
Because AB = AC and ad ⊥ BC, BD = DC, and angle bad = angle DAC;
BD and de are the corresponding chords of the angle bad and the angle DAC respectively. According to the theorem that the corresponding chords are equal if the circumference angles of the same circle are equal, BD = De;
So the answer comes out