If the length of a rectangle is increased by 2 cm, the width is increased by 4 cm, and the area is increased by 60 square cm, what is the original circumference of the rectangle? Sorry, the length and width are increased by 4cm at the same time! In order to apologize, the reward was increased to 100

If the length of a rectangle is increased by 2 cm, the width is increased by 4 cm, and the area is increased by 60 square cm, what is the original circumference of the rectangle? Sorry, the length and width are increased by 4cm at the same time! In order to apologize, the reward was increased to 100

Length + width = (60-4 × 4) △ 4 = 11cm
Perimeter = 11 × 2 = 22 cm

The perimeter of a rectangle is 88cm. If its width is increased by 25% and its length is reduced by half, its perimeter will remain the same as before. What is the original area in square centimeter

The width is x and the length is y
X+Y=88/2
0.25x = half y
Xy = answer to this question
=

The perimeter of the rectangle is 96cm, and the ratio of length to width of the rectangle is 5:3. How many square centimeters is the area of the rectangle?

Because the perimeter is 96
So the length and width is 48
Let the length be x and the width be (48-x)
So x: 48-x = 5:3
X=30 48-30=18
So it's 30 centimeters long and 18 centimeters wide
So the area is 30 * 18 = 540