Quadrilateral ABCD, ad vertical BD, EF diagonal to o, ab = 6, ad = 4 of = 1.5, calculate the circumference of BCEF ABCD is a parallelogram. EF passes through the intersection o of diagonal line and intersects with AB and CD at points E and f respectively

Quadrilateral ABCD, ad vertical BD, EF diagonal to o, ab = 6, ad = 4 of = 1.5, calculate the circumference of BCEF ABCD is a parallelogram. EF passes through the intersection o of diagonal line and intersects with AB and CD at points E and f respectively

The conditions are not homogeneous. What are e and f? Is a quadrilateral an arbitrary quadrilateral, a trapezoid or a parallelogram? What is o? Is it a diagonal intersection?
Or the title has a picture, you didn't draw it
Triangle EBO is equal to triangle ODF (because od = ob, all three angles are equal), so DF = be, so EB + CF = DF + FC = CD
BCEF perimeter = CD + BC + EF = 6 + 4 + 1.5 * 2 = 13

As shown in the figure, in the parallelogram ABCD, if AB = 4, BC = 7, OE = 3, then the perimeter of the quadrilateral EFDC is

There is no picture. The meaning is not clear. Please make it clear

The diagonals AC and BD of parallelogram ABCD intersect at O and EF, passing through O, and intersect AB and CD at e, F, ab = 6, ad = 4, OE = 1.5, respectively

I will not adopt the problem until it is solved

Given that the side length of square ABCD is 2 and point P is a point on diagonal AC, the maximum value of (. AP +. BD) ·(. Pb +. PD) is______

Take a as the coordinate origin, AB as the positive direction of X axis, ad as the positive direction of Y axis to establish a rectangular coordinate system, then a (0, 0), B (2, 0), C (2, 2), D (0, 2), ∵ P points have diagonal AC, let P (x, x), 0 < x < 2, so. AP = (x, x),. BD = (- 2, 2),. Pb = (2-x, - x),. PD = (- x, 2-x) (. AP +. BD) ·(. Pb +. PD) = 4x-4x2 = - 4 (X-12) 2 + 1 when X =12, the maximum value is 1, so the answer is: 1