As shown in the figure, the quadrilateral ABCD is a square. Take AB as the edge, make an equilateral triangle Abe outside the square. The intersection of CE and BD and point F are used to calculate the degree of the angle AFD

As shown in the figure, the quadrilateral ABCD is a square. Take AB as the edge, make an equilateral triangle Abe outside the square. The intersection of CE and BD and point F are used to calculate the degree of the angle AFD

In the equilateral triangle Abe, ∠ Abe = ∠ BAE = ∠ AEB = 60 ° the quadrilateral ABCD is a square ℅ DBC = 45 °∠ ABC = 90 °

As shown in the figure, in the quadrilateral ABCD, point E is on BC, AB / / De, angle B is equal to 78 degrees, angle c is equal to 60 degrees, what is the angle EDC equal to?

Do you have a picture