The perimeter of a rectangle is 64cm, the width is 3 / 5 of the length. What is the area of the rectangle in square centimeter

The perimeter of a rectangle is 64cm, the width is 3 / 5 of the length. What is the area of the rectangle in square centimeter

First, find out the length and width 64 / 2 (1 + 3 / 5) = 32 × 5 / 8 = 20 (CM) - length 20 × 3 / 5 = 12 (CM) - width 20 × 12 = 240cm2. A: the area of this rectangle is 240cm2

The perimeter ratio of the two rectangles is 10; 9. The length to width ratio of the first rectangle is 7:3, and the length to width ratio of the second rectangle is 5:4______ ．

According to the stem analysis, the ratio of the sum of the length and width of the two rectangles is 10:9. Let the sum of the length and width of the first rectangle be 10a, then the length is 10A × 77 + 3 = 7a, and the width is 10a-7a = 3A; if the sum of the length and width of the second rectangle is 9a, then the length is 9a × 55 + 4 = 5a, and the width is 9a-5a = 4A, so the area ratio of the two rectangles is (7a × 3a): (5a × 4a) = 21 The area ratio of two rectangles is 21:20

The perimeter of the two rectangles A and B is equal. It is known that the ratio of the rectangle a to the width is 9:7, and the ratio of the rectangle B to the length is 8:7?

1. The perimeter of a and B rectangles is equal. Suppose that a's length and width are x and y, B's length and width are a and B, then 2 (x + y) = 2 (a + b) 2. If a's length and width ratio is 9:7, then x: y = 9:7, then x = 9 / 7Y. Similarly, a = 8 / 7b can get 16 / 7Y = 15 / 7b from 1,2