The perimeter of a rectangle is 50cm. The length of the rectangle is 50% more than the width. How about the area of the rectangle? Be sure to say why? Step by step

The perimeter of a rectangle is 50cm. The length of the rectangle is 50% more than the width. How about the area of the rectangle? Be sure to say why? Step by step

Sum of length and width: 50 △ 2 = 25 (CM)
Width is "1", length is 1 + 50% = 150%
Width: 250 ÷ (1 + 150%) = 10 (CM)
Length: 10 * 150% = 15 (CM)
Area: 15 * 10 = 150 (square centimeter)

The circumference of a rectangle is 50cm, and the length is 5cm more than the width. Let the length be xcm and the width be YCM. The quadratic equations with 2 variables can be listed

The circumference of a rectangle is 50cm, 5cm longer than the width,
Let the length be xcm and the width be YCM,
The system of quadratic equations with 2 variables that can be listed is
x-y=5
2(x+y)=50
x=15
y=10

It is known that the area s of a rectangle is 72 square centimeters of the root sign, and the length of one side is 50 cm of the root sign, so the length of the other side can be calculated