The perimeter of the bottom of a cube is 16 cm, and its surface area is______ Square centimeter, the volume is______ Cubic centimeter

The perimeter of the bottom of a cube is 16 cm, and its surface area is______ Square centimeter, the volume is______ Cubic centimeter

The edge length of cube is: 16 △ 4 = 4 (CM), the surface area is: 4 × 4 × 6 = 96 (square cm); the volume is: 4 × 4 × 4 = 64 (cubic cm). Answer: the surface area is 96 square cm, the volume is 64 cubic cm. So the answer is: 96 square cm, 64 cubic cm

One cuboid has an area of 8 cubic centimeters, and the other cuboid has an area of 27 cubic centimeters
One cuboid has an area of 8 cubic centimeters, and the other cuboid has an area of 27 cubic centimeters. Together, they form a 432 cubic centimeter cuboid. How many cuboids are there in 8 cubic centimeters and 27 cubic centimeters?

The area is 27 cubic centimeters. I haven't heard that the unit of area is cubic centimeters

If the length of a cuboid is reduced by 2 cm, it becomes a cuboid with a volume of 27 cubic cm

According to the meaning of the title,
Because 27 = 3 × 3 × 3
So the cuboid's width = height = 3cm
Length = 3 + 2 = 5cm
Surface area of primitive cuboid
=5×3×4+ 3×3×2
=60+18
=78 (square centimeter)

A piece of iron wire can be made into a square with a side length of 18cm. Li Gang changed the iron wire into a rectangle. If the length of the rectangle is 27cm, how wide is it

The length of the wire is 18 × 4 = 72cm
Then the circumference of the rectangle is 72cm
Length + width = 72 △ 2 = 36
Length = 27, width = 36-27 = 9cm

With a 16 cm long wire folded into a 5 cm long rectangle, its width () cm. If folded into a square, the area is ()

It's really speechless
Perimeter is 2 width + 2 length
16/2-5=3CM
If it's a square area
16/4=4CM
4²=16CM3
A: the width is 3cm and the area is 16cm3

Use a 60cm iron wire to form a rectangle, so that the width of the rectangle is 2 / 3 of the length, and calculate the length and width of the rectangle

If the length is xcm, the width is 2 / 3xcm
2*（x+2/3x）=60
The solution is x = 18 2 / 3x = 12
So the length is 18cm and the width is 12cm

Use a 60cm long iron wire to form a rectangle, so that the width of the rectangle is 4cm less than the length. 1) calculate the area of the rectangle
2) What is the change in the area of the rectangle? What do you find?

Use a 60cm long iron wire to form a rectangle, so that the width of the rectangle is 4cm less than the length. 1) calculate the area of the rectangle
Length + width = 60 △ 2 = 30
Length = (30 + 4) △ 2 = 17 cm
Width = 17-4 = 13 cm
Area = 13 × 17 = 221 square centimeter
2) What is the change in the area of the rectangle? What do you find?
3 cm;
Long=
(30 + 3) △ 2 = 16.5cm
Width = 16.5-3 = 13.6cm
Larger area
When it comes to
0 cm
L = w = 15cm
Area = 15 × 15 = 225 square centimeter, maximum

Use a 60cm iron wire to form a rectangle, so that the width of the rectangle is 4cm less than the length, and calculate the area of the rectangle

Let the width be X
（x+x+4）*2=60
x=13
13 * (13 + 4) = 221 cm2

In order to maximize the area of the rectangle, the wire with a length of 60cm should be a rectangle____ , wide_____ . maximum area____
Specific ideas

To maximize its area, it must be as long as its width
In this question, length + width = 30cm, which meets the above conditions is length = width = 15cm, and its area is 225cm2

Use a 60cm iron wire to form a rectangle. The length to width ratio of the rectangle is 8:7. Calculate the area of the rectangle

Solution
because
The ratio of length to width is 8:7
So 60 △ 2 = 30
Length: 30 * (8 / 15) = 16
Width: 30 * (7 / 15) = 14
So area = length × width = 16 * 14 = 224
If you don't understand, you can ask