The height of the cuboid wooden box is 8 decimeters, the length is 5 decimeters more than the width, and the volume is 528 cubic decimeters

The height of the cuboid wooden box is 8 decimeters, the length is 5 decimeters more than the width, and the volume is 528 cubic decimeters

Let the width be x and the length be 5 + X
x*(5+x)=528÷8
x²+5x-66=0
(x+11)(x-6)=0
X = 6 or x = - 11
∵ cannot be negative
- 11
5 + 6 = 11cm
A: so the cuboid is 11cm long and 6cm wide

If the perimeter of a rectangle is 12cm and the diagonal is 5cm, then its area is______ ．

∵ the perimeter of the rectangle is 12cm, the sum of length and width is 6cm, let length be xcm, width be YCM, ∵ x + y = 6, ∵ diagonal length be 5cm, ∵ x2 + y2 = 52, ∵ (x + y) 2 = 36, ∵ 2XY = 36-25 = 11, ∵ xy = 11 △ 2 = 5.5, so its area is 5.5cm2

A square with a circumference of 12 cm is transformed into a square with an area of 36 cm and 178 cm. In fact, it is enlarged according to the ratio of (). The length and width of a rectangle are increased by 5 cm respectively
The area increased () CM & # 178;

The first side length is increased by 3cm. The perimeter is 12cm. The side length is perimeter △ 4 = 3. The area is 36cm2. Because the side length is multiplied by the side length. The area is 6 * 6 = 36, so the side length is 6.6-3 = 3. So the side length is increased by 3cm
Second, the length and width are increased by 5cm respectively. The area is directly multiplied by the increased length and width. 5 * 5 = 25. So the increased area is 25C m2
There should be no mistake here

Use the letter formula to calculate. Given the length of the rectangle in the right figure = 8cm, width y = 5cm, find the perimeter C and area sum s of the rectangle

c=（8+5）×2 s=8×5