If the side length of a square is increased by 3 cm, the area will be increased by 45 square cm. The original area of a square is 3 cm______ ．

If the side length of a square is increased by 3 cm, the area will be increased by 45 square cm. The original area of a square is 3 cm______ ．

(45-3 × 3) / (3 + 3), = 36 △ 6, = 6 (CM); the area of the original square: 6 × 6 = 36 (cm 2); answer: the area of the original square is 36 cm 2. So the answer is: 36 cm 2

If the area of a square is equal to the sum of the areas of two squares with side lengths of 3cm and 4cm respectively, then the side length of the square is______ cm．

According to the meaning of the title: the area of the square is 32 + 42 = 25, so the side length of the square is 25 = 5cm

The side length of a square is 3cm, and the area of the other square is 4 times of it. How to find the side length of the second square?

Side length of the second square:
√(3*3*4)
=√36
=6cm

The side length of a square is increased by 3cm, and the area is increased by 45cm. If the side length of the square is reduced by 3cm, the area is reduced by 45cm
What was the original length of the side

1. Let the length of the side be a. according to the equation, we can get (a + 3) ^ 2 = a ^ 2 + 45,
a^2+6a+9=a^2+45
The solution is a = 6
2. Let the length of the side be B. according to the equation, we get (B-3) ^ 2 = B ^ 2-45,
b^2-6b+9=b^2-45
The solution is: B = 9
The first square is 6 cm long and the second is 9 cm long