The cube copper block with the volume of 1dm ^ 3 is placed in the center of the horizontal tabletop with the area of 1m ^ 2. How much pressure does it exert on the tabletop? (g = 10N / kg, flexible copper = 8.9 × 10 ^ 3kg / m ^ 3)

The cube copper block with the volume of 1dm ^ 3 is placed in the center of the horizontal tabletop with the area of 1m ^ 2. How much pressure does it exert on the tabletop? (g = 10N / kg, flexible copper = 8.9 × 10 ^ 3kg / m ^ 3)

(1) M copper = P copper * V copper = 8.9 * 10 ^ 3 * 1 * 10 ^ - 3 = 8.9kg
F = g = m copper g = 8.9 * 10 = 89n
(2)P=F/S=89/1*10^-2=8900Pa
(the stress area is smaller)

There is a cube with a mass of 7.8kg, which is placed in the center of 1m ^ 2 horizontal table, and the pressure produced by the cube is 7.8 * 10 ^ 3PA
What is the pressure and area of the table? (g = 10N / kg)

N = G = mg =(7.8 kg)(10 N/kg) = 78 N
S = N/P = (78 N)/(7.8 kPa) = 0.01 m^2

Half of the square metal block with a side length of 10 cm is placed on the table with an area of 1 square meter. The spring dynamometer shows that the indication is 10 N and the pressure is 4000 PA
Find the density. (g takes 10 N)

1 * 10 to the third power of kg / M