A cube copper block with side length of 0.1M is placed on the horizontal table top of 1 square meter, and the pressure of the copper block on the horizontal table top is calculated Density of copper block = 8.9 times 10 cubic kg / m3

A cube copper block with side length of 0.1M is placed on the horizontal table top of 1 square meter, and the pressure of the copper block on the horizontal table top is calculated Density of copper block = 8.9 times 10 cubic kg / m3

G = mg = density VG = 89n
p=F/S=G/S=89N/0.01M^2=8900Pa

What is the pressure of a cube with a weight of 2.5n and a side length of 0.1m2 placed in the center of a horizontal table
If the object is cut half in the vertical direction, what is the pressure of the remaining part on the table

From P = f / s, P = 2.5n/0.1m2 = 25Pa
If half is cut along the vertical direction and the gravity is halved, that is, the pressure produced is halved and the contact area is also halved, then the pressure remains unchanged, or 25Pa

A square wood block with a mass of 0.6kg and a side length of 0.1M is placed on a horizontal table in a cylindrical container with a bottom area of 200cm2 and a water height of 25cm. (g = 10N / kg, ρ water = 1 × 103kg / m3)
(1) What is the density of the forest block?
(2) What is the pressure of water on the bottom of the container when the wood block is not placed?
(3) How many kilogram hook yards must be put on the block to make it just submerged in water

（1）v=（0.1m）3=0.001m3,
ρ wood m wood V=
0.6kg0.001m3 =0.6×103kg/m3；
(2) P = ρ, water GH = 1.0 × 103kg / m3 × 10N / kg × 0.25m = 2500pa;
(3) G wood = m wood, g = 0.6kg × 10N / kg = 6N,
△p=
△Fs=
G wood s=
6N200×10-4m2=300Pa；
(4) F floating = ρ water GV drainage = 1.0 × 103kg / m3 × 10N / kg × 0.001m3 = 10N
G code = f float-g wood = 10n-6n = 4N
M code=
G code G=
4N10N/kg=0.4kg．

A square metal block with a side length of 0.1M and a mass of 2.7kg
A square metal block with a side length of 0.1M and a mass of 2.7kg is calculated as follows: (1) the density of the metal block; (2) the pressure on the table when the metal block is placed in the center of the horizontal table top; (3) the buoyancy of the metal block when the metal block is immersed in alcohol

Density = mass divided by volume = m divided by V = 2.7kg divided by 0.1M to the third power = 27x10 to the third power kg / m3
P = f divided by S = MGS = 2.7kgx9.8n / kg divided by (0.1M Square) = 2646pa
F = alcohol density times V metal times g = 0.8 × 10 ^ 3kg / m ^ 3 times (0.1M cubic) x9.8n/kg