The surface area of the cuboid is reduced by () cm by sawing a 10 cm long, 8 cm wide and 8 cm high cuboid into the largest cube No direct answers,

The surface area of the cuboid is reduced by () cm by sawing a 10 cm long, 8 cm wide and 8 cm high cuboid into the largest cube No direct answers,

The width and height of the remaining cuboids are 8cm and the length is 10-8 = 2cm,
Volume:
8x8x (10-8) = 128 CC
Surface area:
8x2 X4 + 8x8x2 = 192 cm2

How many square decimeters can the surface area of timber increase at most and how many square decimeters at least
Why?

Up to 120 square decimeters
A minimum increase of 12 square decimeters

A cuboid wood, 4 meters long, 0.5 meters wide, 0.2 meters thick, saw it into 4 sections, the surface area at least increased () square decimeters

It only needs three saws to cut it into four sections, so six more faces are added
The minimum increase of surface area, that is, the area of the increased surface needs to be the minimum, so the area of each surface is 2 * 5 = 10 square decimeters
The area of six additional surfaces is 6 * 10 = 60 square decimeters
A minimum increase of (60) square decimeters in surface area

A 3 m long cuboid wood is sawed into three sections. The sum of the surface area of the three sections is 24 cm3 more than that of the original cuboid. The original volume of the wood is calculated
How much? Urgent

The cuboid wood is sawed into three sections, and the sum of the surface area of the three sections is four more sections than that of the original cuboid
3M = 300cm
A cross-sectional area = 24 △ [(3-1) × 2] = 6 square centimeters
Original volume of wood = 6 × 300 = 1800 cubic centimeter