If the length and width of a square test field are increased by 5 meters, the area will be increased by 875 square meters? Draw a picture first, then answer

If the length and width of a square test field are increased by 5 meters, the area will be increased by 875 square meters? Draw a picture first, then answer

The drawing is as follows: let the length of the original square be a. according to the meaning of the title, we get (a + 5) (a + 5) - A2 = 875, & nbsp; & nbsp; & nbsp; A2 + 10A + 25-a2 = 875, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 10A + 25 = 875, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp

If the side length of a square test field is increased by 5 meters, the area will be increased by 825 square meters. How many square meters is the original test field?
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Draw a picture. First, draw the picture in the title
The increased area is two rectangles, overlapping a square with side length of 5 (5 * 5 = 25)
The sum of two rectangular areas 825 + 25 = 850
The volume of a rectangle is 850 / 2 = 425 (width is 5)
The length of this rectangle is 85
The original side length of this square is 85-5 = 80
The area is 80 * 80 = 6400
This is obviously a primary school problem, which can't be explained by equation

The side length of a square is increased by 5 cm, and its area is 96 cm more than the original. How much is the original

Let the original side length be X
(x+5)²-x²=96
10x + 25=96
x=7.1

How many points does a square increase in area if its side length is increased by 1 / 5

(1+1/5)×(1+1/5)-1×1
=36/25-1
=11/25
So it's 11 out of 25

The side length of a square is 5 meters. After extending its side length by one fifth, the area will be increased by several parts

The side length is 5 × (1 + 1 / 5) = 6
Therefore, the increase of (6 × 6 × 6-5 × 5 × 5) / (5 × 5 × 5) = 91 / 125

The side length of a square is 6dm. If the side length of the square is increased by one third, how much DM will the area increase?
It's due on September 27th!

When the side length is increased by one third from 6dm, the formula is: 6dm multiplied by one third equals 8dm
The square area calculation formula is: side length multiplied by side length
So the changed area is: 8dm times 8dm equals 64dm square
The previous area was: 6dm times 6dm equals 36dm square
So the area increased: 64dm square - 36dm square = 28dm square

If the side length of a square is increased by 1 / 2, what is the area of the new square?

Is (1 + 1 / 2) × (1 + 1 / 2) = 9 / 4

If the side length of a square is increased by one centimeter, the area will be increased by seventeen centimeters. What is the area of the original square

What is added is actually a small square with side length of 1, and two rectangles with side length of 1 and side length of original side. You can understand it by drawing the figure below,
What is the area of the two rectangles
17－1＝16
So the area of a rectangle is
16÷2＝8
So the original side length is
8÷1＝8
So the area of the original square is
8 × 8 = 64 square centimeter

If the length of each side of a square is increased by one centimeter, the area will be increased by 17 centimeters. What is the area of the original square?

If the length of each side of a square is increased by 1 cm, the area will be increased by 17 cm. What is the area of the original square?
The side length of the square is (17-1 × 1) △ 2 △ 1 = 8 cm
Square area 8 × 8 = 64 square centimeter

If the side length of a square is increased by 1 cm, the area will be increased by 17 cm

(x+1)²-x²=17
x²+2x+1-x²=17
2x+1=17
2x=16
x=8
8²=64
The original side length of the square is 8 cm, the original square area is 64 square cm