Two parallelograms A and B are overlapped. The area of the overlapped part is one fourth of a and one sixth of B. the area of a is 12 square centimeters

Two parallelograms A and B are overlapped. The area of the overlapped part is one fourth of a and one sixth of B. the area of a is 12 square centimeters

If the area of the overlap is one fourth of that of a, the area of the overlap is 12 × 1 / 4 = 3 square centimeter,
If the area of the overlap is one sixth of that of B, then the area of B is 3 / 1 / 6 = 18 square centimeter
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Two parallelograms A and B are overlapped. The overlapping area is 1 / 4 of a and 1 / 7 of B. We know that the area of a is 12 square centimeters, and how many square percent more than that of a

12*1/4=3
3 * 7 = 21 is 21