The school meeting room is paved with square bricks. 360 square bricks with a side length of 3 DM, and how many square bricks with a side length of 4 DM?

The school meeting room is paved with square bricks. 360 square bricks with a side length of 3 DM, and how many square bricks with a side length of 4 DM?

Let x bricks be needed. According to the meaning of the question, 4 × 4 × x = 3 × 3 × 360, 16x = 3240, x = 202.5. A: 202.5 square bricks are needed

It takes 2400 pieces to pave a small road with 0.3 meters long square bricks. If we use 0.4 meters long square bricks instead, how many square bricks do we need? (using proportional knowledge)

Suppose x square bricks are needed. According to the meaning of the question: 0.42 × x = 0.32 × 2400, & nbsp; 0.16x = 216, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 1350; a: 1350 square bricks are needed

A classroom needs 400 square bricks with a side length of 3DM. How many square bricks do you need if you use a side length of 4dm

3dm×400＝4dm×X
The solution is 1200dm & sup2; = 4xdm & sup2;
1200÷4 ＝X
300 ＝X
X ＝300