Increase the length and width of a rectangle by 1 / 4. The area ratio of the current rectangle to the original rectangle is ()

Suppose the original width is 4, the length is 8 and the area is 32
Now it's 5 wide, 10 long and 50 square meters
25：16

The length and width of a rectangle are increased by 2 meters, and the area of the new rectangle is increased by 20 square meters compared with the old one

A*B+20=(A+2)*(B+2)
A+B=8
The answer comes out, but it's not unique, such as 1 and 7, 2 and 6, 3 and 5, or 2.5 and 5.5, as long as the sum equals 8

One side of a square is reduced by 1 / 5, and the other side is increased by 2 meters to get a rectangle. The area of the rectangle is equal to that of the original square. How many meters is the length of the original square?

Let the length of the original square be a,
（1-4/5）aX(a+2)=aXa
a=8
The original square is 8 meters long

One side of a square is reduced by 10%, and the other side is increased by 2 meters to get a rectangle whose area is equal to that of the original square,
How many meters is the side length of the original square

18 meters, the equation is solved
Let X be a square edge
X^2=(X-10%X)(X+2）
No, I didn't come up with an equation

After the length and width of a rectangle are increased by 1 / 2, what is the area ratio of the rectangle to the original rectangle?

Suppose the length and width of a rectangle are x and y, respectively, and the area is XY
When the length and width are increased by 1 / 2 respectively, they are (x + 1 / 2x) = 3 / 2x, (y + 1 / 2Y) = 3 / 2Y, and the area is: 3 / 2x * 3 / 2Y = 9 / 4xy
Therefore, the area ratio of the rectangle to the original rectangle is: 9 / 4xy: xy = 9:4

If you draw a rectangle at will, the length and width will be increased by 1 / 3 respectively. What is the original area of the rectangle?
How much more than the original area?

Example:
Original: length: 10M, width: 5m
Area: 10x5 = 50 (M2)
Now: length: 10x (1 + 1 / 3) = 40 / 3 (m)
Width: 5x (1 + 1 / 3) = 20 / 3 (m)
Area: 40 / 3x20 / 3 = 800 / 9 (M2)
50 divided by 800 / 9 = 9 / 16
It is found that the area of the first rectangle is 9 / 16 of the original

If you increase the length and width of a cuboid by 1 / 3 respectively, what is the area of the cuboid now? What do you find?

If the length of a cuboid is increased by 1 / 10 and the width is decreased by 1 / 10, then the area of the cuboid is increased or decreased compared with that of the original cuboid?
Formula, meaning

It's down. It's down by one percent

If the length and width of a rectangle are increased by one third respectively, the area of the rectangle is now a fraction of the original

Increase 1 / 3, then the length and width become 4 / 3 of the original, then the area is equal to length multiplied by width, and becomes 16 / 9 of the original

The ratio of length to width of a rectangle is 7:5. If the width is increased by 14 cm, the rectangle will become a square. What is the area of the original rectangle
If the length of a rectangle is reduced by 1.5 meters or 1.2 meters, its area will be reduced by 6 square meters. What is the area of the rectangle? A trapezoid has a ratio of 4:9 between the upper and lower bottom. If the lower bottom is reduced by 15 cm, it will become a square. What is the ratio of the area of the square to that of the original trapezoid, What is the area of an isosceles triangle? If the two sides of an isosceles triangle are 2 cm and 3.5 cm long, then the circumference of the triangle is several cm or several cm

1: 1715 (cm2) 2:3:8 vs 13 4:5 π 5:7.5 or 9

Increase the length and width of a rectangle by 1 / 4. The area ratio of the current rectangle to the original rectangle is ()