Given that the function y = log2 (x2-ax + 1) has a minimum value, then the value range of a is?

Given that the function y = log2 (x2-ax + 1) has a minimum value, then the value range of a is?

If we don't consider the range of X, log2 is simple increasing, and x2-ax + 1 always has a minimum, so a should belong to R. if we consider that x belongs to R, then we need x2-ax + 1 > 0, quadratic function characteristic - 2

If y = log2 ^ (x ^ 2 + ax + 1) is monotone on [2,3], then the value range of a

Let g (x) = x ^ 2 + ax + 1
Y is monotone in [2,3], so g (x) must be monotone in this interval
That is, the axis of symmetry x = - A / 2 of G (x) is not in this interval
So - A / 2 > = 3 or - A / 2

If the image of a function y = KX + B passes through a (0, - 2), B (1,0), then B = () k = ()
The answer is - 2 = 0kx + B (1), 0 = 1kx + B (2) get b = - 2, bring B = - 2 into (2) get 0 = K-2 = 2, k = 2

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