The image with positive scale function y = KX (K ≠ 0) is a straight line passing through who and who; the image with linear function y = KX + B (K ≠ 0) passes through who and who

The image with positive scale function y = KX (K ≠ 0) is a straight line passing through who and who; the image with linear function y = KX + B (K ≠ 0) passes through who and who

1:(0,0)
2:(0,b)

Area of inverse scale function image
Two points a (2,1) B (1,2) (symmetric with respect to y = x) on inverse scale function y = 2 / X
The area of the so-called graph formed by the line AB and the inverse scale function is?

Use definite integral. Integral (1 ~ 2) [(- x + 3) - (2 / x)] DX = (3 / 2) - 2ln2. Right?

As shown in the figure, take the point P on the image of the linear function y = - x + 5 and make the PA ⊥ X axis and Pb ⊥ Y axis; if the perpendicular foot is B and the area of the rectangular OAPB is 6, then the number of such points P has ()
A. 1B. 2C. 3D. 4

Let the coordinates of point p be (x, y), then we get | x | y | = 6 from the image, then we substitute y = - x + 5 to get x (- x + 5) = ± 6, then x2-5x + 6 = 0 or x2-5x-6 = 0, and the equation has two unequal real roots, so we choose D

For any point P on the image with inverse scale function y = x / a (a is not equal to 0), make PA ⊥ X axis and Pb ⊥ X axis, and the perpendicular feet are a, B, and opab
The area is 6. Find the analytic expression of the inverse scale function
Dear friends, fast. Fast, good bonus points

Is this an inverse proportional function?
This is a positive proportional function. If it is y = A / X (i.e. y = A / x)
If so:
Let P (x, y)
Opab forms a rectangle
So 6 = x * y
And because y = a of X
So 6 = x * (A / x) is a = 6
So the analytic formula is y = 6 / X