Given the linear function Y1 = - x + 3 and y2 = 3x-1, when x takes what value, Y1 > Y2? Y1 = Y2? Y1

Given the linear function Y1 = - x + 3 and y2 = 3x-1, when x takes what value, Y1 > Y2? Y1 = Y2? Y1

1. Y1 > Y2, so - x + 3 > 3x-1, 4x < 4, x < 12, Y1 = Y2, so - x + 3 = 3x-1, 4x = 4, x = 13, Y1

Given the image intersection (2, - 1) of the function Y1 = kx-2, y2 = - 3x + B, when x takes what value, Y1 < 0 and Y2 < 0

(1) Substituting the coordinates of point a into Y1, we can get 2k-2 = - 1, that is, k = 12; substituting the coordinates of point a into Y2, we can get: - 6 + B = - 1, that is, B = 5; the analytic expressions of the two functions are: Y1 = 12x-2, y2 = - 3x + 5; as shown in the figure; (2) from the image, we can see: ① when x < 2, Y1 < Y2; ② when x ≥ 2, Y1 ≥ Y2; 3) ∵ straight line Y1

Given that the functions Y1 = kx-2 and y2 = - 3x + B intersect at point a (2, - 1)
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It is known that (- 5, Y1), (3, Y2) is a linear function y = - 1 / 3x + 2, and the relationship between Y1 and Y2 is
Is it greater than or less than or equal to

y1>y2
Because this first-order function is a monotone decreasing function