Given the equation 3x-2y = 1, it is written that y is a first-order function of X

Given the equation 3x-2y = 1, it is written that y is a first-order function of X

3x-2y=1
2y=3x－1
y=3／2x－½

If 2Y is positively proportional to 3x-1, when x = 3, y = 4, find the functional expression of Y and X

Let 2Y = K (3x-1), then y = 1 / 2K (3x-1)
When x = 3, y = 4K = 4
So k = 1
So y = 3x-1

How to transform the equation 3x + 2Y = 6 into the form of linear function
How does the equation 3x + 2Y = 6 turn into a function of y = - 3 / 2x + 3 (y = minus three-thirds x + 3)? I'm previewing the junior high school course. Please write the process clearly. The more detailed, the better. It seems a little confused!... hee hee~

3x+2y=6
So 2Y = 6-3x
=-3x+6
The equation still holds when both sides divide by two at the same time
So y = = - (3 / 2) x + 3

y=-3x,-2≤x

Only when - 2 ≤ x