Given the linear function Y1 = - 3x-4 and y2 = 5x-20, when x takes what value, the function Y1 is not less than Y2?

Given the linear function Y1 = - 3x-4 and y2 = 5x-20, when x takes what value, the function Y1 is not less than Y2?

x

Using image method to solve equations: 5x + 4Y = 13X − 2Y = 5

According to the first equation, we can get y = - 54x + 14, when x = 0, y = 14, when x = 1, y = - 1. According to the second equation, we can get y = 32x-52, when x = 0, y = - 52, when x = 1, y = - 1. The image is as shown in the figure

If we know that the alternating current of the image with the first-order function y = 4x-1 and the first-order function y = 3x-b is in the third limit, then the value range of B is -------

y=4x-1=3x-b
x=1-b
The third quadrant is X

Given that the image of a function y = 1 / 3x + 2B passes through (- 1, - 2) points, the coordinates of the intersection of the image and the x-axis are obtained
Problem 2: given that the straight line y = - KX + 2b is parallel to y = x + 3 and passes through (- 1, - 2), find the analytic expression of the first-order function

1.
Substituting (- 1, - 2) into y = 1 / 3x + 2B
b= -5/6
y=1/3x-5/3
Let y = 0
x=5
Intersection of image and X axis (5,0)
two
Because the line y = - KX + 2b is parallel to y = x + 3
So y = x + 2B
Substituting (- 1, - 2) into y = x + 2B
b= -1/2
y=x-1