1. When m satisfies (), the image of the first-order function y = 3x = M-4 intersects the y-axis on the negative half axis; when m satisfies (), the image of the function y = - 2x-m + 2 intersects the x-axis Correction: 1. When m satisfies (), the image of the linear function y = 3x = M-4 intersects the y-axis on the negative half axis; when m satisfies (), the image of the function y = - 2x-m + 2 intersects the x-axis on the positive half axis What is the intersection of function = y = - 5x + 2 and X axis? What is the point of intersection with the y-axis? What is the area of the triangle enclosed by two coordinates?

1. When m satisfies (), the image of the first-order function y = 3x = M-4 intersects the y-axis on the negative half axis; when m satisfies (), the image of the function y = - 2x-m + 2 intersects the x-axis Correction: 1. When m satisfies (), the image of the linear function y = 3x = M-4 intersects the y-axis on the negative half axis; when m satisfies (), the image of the function y = - 2x-m + 2 intersects the x-axis on the positive half axis What is the intersection of function = y = - 5x + 2 and X axis? What is the point of intersection with the y-axis? What is the area of the triangle enclosed by two coordinates?

1. Linear function y = 3x = M-4
This should be y = 3x + M-4?
∵k〉0
In the first, third and fourth quadrant, y = 3x + M-4
∴m-4〈0
m〈4
y=-2x-m+2
∵k〈0
In the first, second and fourth quadrants, y = - 2x-m + 2
∴m-2〉0
m〉2
When y = 0, substitute y = - 5x + 2
X=2/5
When x = 0, substitute y = - 5x + 2
Y=2
The point of intersection with X axis (2 / 5,0), the point of intersection with y axis (0,2)
Triangle area = 1 / 2 * 2 / 5 * 2 = 2 / 5

If we know that the images of the linear functions y = 3x + m and y = LX + n pass through the point P (negative 2,0) and intersect the Y axis with the points B and C respectively, then
What is the area of △ PBC? There should be a detailed process. Please, hurry!

Substituting P (- 2,0) into the linear equation, we get the following results
3+m=0
m=-3
1+n=0
n=-1
The intersection B of the line y = - (3 / 2) x-3 and y-axis is (0, - 3)
The intersection point C of the line y = (- 1 / 2) X-1 and y-axis is (0, - 1)
Then, the area of △ PBC = (3-1) * 2 / 2 = 2