Why can the vector translation point be directly moved, while the function needs to be done by undetermined coefficient method?

Why can the vector translation point be directly moved, while the function needs to be done by undetermined coefficient method?

The point has no independent variable and dependent variable, so it moves directly. The rule of bringing into the function is to use X to express the translation relationship of the new coordinate

Image law of parallel or translation of two straight lines

If Y1 = K1X + B1 and y2 = k2x + B2, when K1 = K2, the two lines are parallel, and vice versa
When the straight line y = KX + B moves up C units, the analytic expression of the function is y = KX + B + C; when the straight line y = KX + B moves down C units, the analytic expression is y = KX + B-C, that is, y value plus minus
When the line y = KX + B moves h units to the left, the analytic expression of the function is y = K (x + H) + B, and to the right, the analytic expression is y = K (X-H) + B, that is, the independent variable x is left plus right minus

In the plane rectangular coordinate system, the rule of translating the image of a function analytic formula to the left, right, up and down
There are better examples ~ mmm. 0 points can be added
Like this: y = 2x-1 translation up, translation down, translation left, translation right. Write down the steps like left plus right minus, because you want to understand it thoroughly. So it will be more wordy

Left plus right subtraction the original x is changed to (x ±...) x, and the coefficients before X are placed outside the brackets to move up and down. It is relatively simple to add and subtract the constant term directly on the last side