On the solution of sine function area Know: y = sin (3x - п / 2) = a (0 < a > 1) find: sum of all real number roots in the interval [0,2 Π]
For sine function integral, the product from 0 to 2 π is enough
Excuse me, how to calculate the period of sine function?
If y = asin (ω T + φ), then the period T = 2 π / ω