The operation of quadratic equation: 1, 2x-y-1 equal to 0 and x ^ 2-y ^ 2 = 0, 2, 2x-y-1 greater than 0 and x ^ 2-y ^ 2 less than 0

The operation of quadratic equation: 1, 2x-y-1 equal to 0 and x ^ 2-y ^ 2 = 0, 2, 2x-y-1 greater than 0 and x ^ 2-y ^ 2 less than 0

1. From the question 2x-y-1 = 0, we can get y = 2x-1
And ∵ x ^ 2-y ^ 2 = 0, ∵ x ^ 2 = (2x-1) ^ 2, that is, 3x ^ 2-4x + 1 = 0
The solution is: x = 1, y = 1 or x = 1 / 3, y = - 1 / 3
2. By sorting out the questions, we can get YX ^ 2. The solution is a region composed of innumerable points, which is divided into two parts. If you have any questions, please let me know

Is the square of X equal to the solution of x 0 and 1

x²-x=0
x(x-1)=0
X = 0 or x = 1
Your conclusion is correct. I hope to adopt it

Are y-x-1 = 0 and X + 1-y = 0 equal to the same line

Equal to, all changed to x + 1 = y