The vertex coordinates of the parabola y = 2 (x-3) 2 + 1 are () A. （3，1）B. （3，-1）C. （-3，1）D. （-3，-1）

The vertex coordinates of the parabola y = 2 (x-3) 2 + 1 are () A. （3，1）B. （3，-1）C. （-3，1）D. （-3，-1）

The vertex coordinates of the parabola y = 2 (x-3) 2 + 1 are (3, 1)

What is the vertex coordinate of parabola y = 1 / 2 (square of x) + 3

Vertex coordinates (- B / 2a, 4ac-b square / 4A) = (0,3)

It is known that the intersection of the straight line y = 2x + 3 and the square of the parabola y = x + 8x + 11 is a, B, and the vertex of the parabola is c. the area of the triangle ABC is calculated

Because of the time, only the method
In the first step, the coordinates of AB are obtained by two expressions;
The second step is to find the length of AB by using the distance formula between two points;
The third step is to find the vertex of the parabola;
The fourth step is to find the distance from the vertex to the straight line, which is the height of the triangle;
Using triangle area formula to calculate area

Given that a focus of the ellipse x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 = 1 is (√ 2,0), and the chord length of the tangent line x = √ 2 is 4 √ 6 / 3, then the elliptic equation is
Writing process

A^2-B^2=2
The original ellipse (radical 2,2 radical 6 / 3) is substituted
B2=4
A2=6
So x ^ 2 / 6 + B ^ 2 / 4 = 1