If the abscissa of the intersection of the image with the inverse scale function y = K / X and the image with the positive scale function y = 4x is - 2, then the analytic expression of the inverse scale function is -

If the abscissa of the intersection of the image with the inverse scale function y = K / X and the image with the positive scale function y = 4x is - 2, then the analytic expression of the inverse scale function is -

solution
Abscissa of intersection = 2
Then ordinate = 2x4 = 8
k=xy
k=16
So function
The analytical formula is
y=16/x
I don't know how to ask

The intersection coordinates of the image with inverse scale function y = 2 / X and positive scale function y = 4x in the first quadrant are?

Explanation
Y = 2 / X and y = 4x
LIANLI Xiaode
4x=2/x
That is, x ^ 2 = 2 / 4
The solution is x = √ 2 / 2 or x = - √ 2 / 2
When x = √ 2 / 2, y = 2 √ 2,
When x = - 2 / 2, y = - 2 √ 2,
know
Images with inverse scale function y = 2 / X and positive scale function y = 4x
The intersection points of (√ 2 / 2,2 √ 2) and (- √ 2 / 2, - 2 √ 2)
Therefore, the intersection coordinates of the function y = 2 / X and the positive scale function y = 4x in the first quadrant are (√ 2 / 2,2 √ 2)

It is known that y is the inverse proportional function of X, when x = radical 3. Y = negative radical 2. Find the analytic expression of the function and the value of the function when x = radical 6

y=k/x
Then k = XY
So k = √ 3 × (- √ 2) = - √ 6
So y = - √ 6 / X
x=√6
y=-√6/√6=-1

A new function is obtained by translating the image of function y = 3 / 3 root 3x up two units, and the two function images before and after translation

I say the slope of the method function is √ 3 / 3
Take a point (1, √ 3 / 3) and translate it up 2 units on the image to get (1,2 + √ 3 / 3)
If the slope is not changed, the analytic expression of the new function can be obtained by using a slope and a point

Shift the image of function y = 2 radical (x) + radical [x (x-1)] one unit to the left, and then shift up two units to get the image of y = f (x)
Then the domain of y = f (x) is

y=2√x+√[x(x-1)]
Shift 1 unit to the left: Y1 = 2 √ (x + 1) + √ [(x + 1) x]
And then translate 2 units up to f (x) = 2 √ (x + 1) + √ [(x + 1) x] + 2
The definition field of F (x) must satisfy: x + 1 > = 0, and (x + 1) x > = 0
That is to say, its definition field is x > = 0

The m-th power of the line y = 3x plus m + 1 is translated upward by 2 units. What is the analytical expression of the function after translation?
M power of y = 3x plus m + 3 or y = 3x + 4?

The m power of y = 3x plus m + 3

The analytic formula of the first-order function y = 2x + 1 image moving two units to the right?

The independent variable is left plus right minus, y = 2 (X-2) + 1 = 2x-3

If the line y = 2x-1 is shifted upward by 1 unit, the image of a first-order function is obtained, then the analytic expression of the first-order function is obtained
The analytic expression is____________ .

y=2x

Given a function y = KX + B image can be seen as a straight line y = 2x up six units of length obtained, please, finish it can play computer
It is known that the image of the first-order function y = KX + B can be obtained by translating Six unit lengths of the straight line y = 2x upward, and the area of the triangle surrounded by y = KX + B and two coordinate axes is divided into two parts with the ratio of area of 1:2 by a positive proportion function

The image of: y = KX + B is obtained by translating y = 2x upward by 6 unit lengths. The analytic expression of the first-order function is: y = 2x + 6. As shown in the figure, the area of the triangle surrounded by y = 2x + 6 and two coordinate axes is s △ AOB = = 9, and it is divided into two parts with an area of 1:2 by a positive proportion function

How to draw the image after inverse scale function translation, such as 3-2x / X-2 image

Up + down - (y = * Change of *)
Left + right - (x change of expression)
3-2x / X-2 changes in the direction of y = K / x, (3-2x + 1-1) / X-2 = - [1 / (X-2)] - 2
-The - 2 in [1 / (X-2)] is the change of X, so (1) y = - 1 / X moves right by 2 unit lengths
-The - 2 in 2 is a * change, so it shifts down 2 unit lengths on the basis of (1)