The image of the known function y = - 3x + 2 intersects the Y axis at point a 1. Then the coordinate of point a is 2. The analysis of the straight line obtained by translating the straight line y = - 3x + 2 upward one unit length 3. Find the analytical formula of the straight line obtained by translating the straight line y = - 3x + 2 upward by two unit lengths. 4. Find the analytical formula of the straight line y = - 3x + 2 with respect to the y-axis symmetry

The image of the known function y = - 3x + 2 intersects the Y axis at point a 1. Then the coordinate of point a is 2. The analysis of the straight line obtained by translating the straight line y = - 3x + 2 upward one unit length 3. Find the analytical formula of the straight line obtained by translating the straight line y = - 3x + 2 upward by two unit lengths. 4. Find the analytical formula of the straight line y = - 3x + 2 with respect to the y-axis symmetry

3,y=-3x+4
4,y=3x+2

Given that the maximum value of function f (x) = asinx + B is 2 and the minimum value is 0, find the real number ab

The maximum value of SiNx is 1 and the minimum value is - 1,
From the known
a＋b=2
-a+b=0
∴a=1
b=1
∴ab=1×1=1

Given that the function f (x) = asinx + B (a < 0, B ∈ R) has a maximum of 5 and a minimum of - 1, find the values of a and B and the minimum positive period of G (x) = bcos (AX)

The minimum positive period of − a + B = 5A + B = − 1, a = − 3B = 2, G (x) = bcos (AX) is 2 π|a | = 2 π 3

The known function y = asinx + B (a)

A:
y=asinx+b,a

It is known that: as shown in the figure, the image of the primary function with y = - 2x + 3 intersects with X axis and Y axis at two points a and C respectively, the image of the secondary function with y = x2 + BX + C passes through point C, and intersects with the primary function at another point B in the second quadrant. If AC: CB = 1:2, then the vertex coordinates of the secondary function are___ ．

∵ if the image of a linear function with y = - 2x + 3 intersects with X axis and Y axis at two points a and C respectively, let x = 0 and y = 0 respectively, then a (32,0) and C (0,3) can be obtained. Because point B is on the image of a straight line with y = - 2x + 3, let B (x, - 2x + 3), and let AC: CB = 1:2 know that x2 + (- 2x + 3-3) 2 = 2 (32) 2 + 32, then - 2x

Given that the image of quadratic function y = x ^ 2 + BX + C intersects with X axis at two points B and C, intersects with y axis at point a, and BC = 2, the area of triangle ABC is equal to 3, find the intersection of a and C

|c|*2*1/2=3
|c|=3
BC^2=(b)^2-4c=b^2-4c=4
c=3,b=±4
C = - 3, B has no solution
So: B = ± 4, C = 3

If the graph of quadratic function y = AX2 + BX + C is shown in the figure, then the error in the following relation is ()
A. a＜0B. c＞0C. b2-4ac＞0D. a+b+c＞0

A. The opening of the quadratic function is downward, a < 0, correct, does not conform to the meaning of the problem; B, the intersection of the quadratic function and the Y axis is on the positive half axis, C > 0, correct, does not conform to the meaning of the problem; C, the quadratic function has two intersections with the X axis, b2-4ac > 0, correct, does not conform to the meaning of the problem; D, when x = 1, the value of the function is negative, a + B + C < 0, wrong, conforms to the meaning of the problem, so choose D

For the image of quadratic function y = AX2 + BX + C, as shown in the figure, its axis of symmetry is a straight line x = - 1, then the correct number of the following conclusions is
1 a＞0 b＜0
2 a-b+c＜0
3 2a-b=0
4 b²-4ac＞0
5 2a+b＞0
A one B two C three D four
The graph can't be passed on. The intersection of the opening upward a is greater than 0 and the Y axis below the X axis C is less than 0 B

The correct answer is 2,3,4,5
First, with the opening upward, we can see that a > 0 and the axis of symmetry x = - B / 2A = - 1
We know: B = 2A > 0, so 1 is wrong
B = 2A has: 2a-b = 0, so 3 is correct
Both a and B are greater than 0, so 2A + B is greater than 0, so 5 is correct
Because the intersection point with the Y axis is below the X axis, we can see that the ordinate of the fixed point is: (4ac-b ^ 2) / 4A < 0, the denominator is greater than 0, so the numerator is less than 0, that is: B ^ 2-4ac > 0, so 4 is correct
Because B = 2A, C < 0, so A-B + C = a-2a + C = - A + C < 0 holds, so 2 is correct
So, there are four right answers and one wrong one

The abscissa of each point on the image of the function y = sin (2x + π / 4) is extended to 2 times of the original, and then it is shifted to the right by π / 4 units
The function of is ()
A f（x）=sin x
B f（x）=cos x
C f（x）=sin 4x
D f（x）=cos 4x

Double abscissa means that 2x / 2 shifts to the right, π / 4 units means that π / 4 is subtracted, so choose a

Given that f (x) = 2Sin (ω x + φ), (ω > 0, | φ | ≤ π 2) is monotone on [0,4 π 3], and f (π 3) = 0, f (4 π 3) = 2, then f (0) is equal to ()
A. -2B. -1C. -32D. -12

∵ f (x) = 2Sin (ω x + ∈) is monotone on [0,4 π 3], and f (π 3) = 0 < 2 = f (4 π 3), ∵ y = f (x) is monotone increasing on [0,4 π 3], and 14T = 4 π 3 - π 3 = π, ω > 0, ∵ t = 2 π, ω = 4 π, ∵ ω = 12, and π 3 × 12 + φ = 2K π, K ∈ Z; ∵ φ = 2K - π 6, K ∈ Z, and